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What is the units digit of \(17^{27}\)?

A. 1

B. 2

C. 3

D. 7

E. 9

In such questions, we need to look for pattern
Units digits of powers of 7

1--- 7
2--- 9
3--- 3
4--- 1
5--- 7 again
So multiples of 4 have unit digit 1.
28 will have unit digit 1
27 will have 3

So C

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What is the units digit of \(17^{27}\)?

When we need to find units digit of any power then units digit is same as the units digit of the base raised to the exponent.

=> Units digit of \(17^{27}\) = Units digit of \(7^{27}\)

Now to find the unit's digit of \(7^{27}\), we need to find the pattern / cycle of unit's digit of power of 7 and then generalizing it.

Unit's digit of \(7^1\) = 7
Unit's digit of \(7^2\) = 9
Unit's digit of \(7^3\) = 3
Unit's digit of \(7^4\) = 1
Unit's digit of \(7^5\) = 7

So, unit's digit of power of 7 repeats after every \(4^{th}\) number.
=> We need to divided 27 by 4 and check what is the remainder
=> 27 divided by 4 gives 3 remainder

=> \(7^{27}\) will have the same unit's digit as \(7^3\)
=> Unit's digits of \(7^{27}\) = 3

So, Answer will be C
Hope it helps!

Link to Theory for Last Two digits of exponents here.

Link to Theory for Units' digit of exponents here.
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