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07 Feb 2020, 17:43
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
58% (02:10) correct
42%
(02:03)
wrong
based on 84
sessions
History
Date
Time
Result
Not Attempted Yet
What is the value of \(\frac{(2a + 6a − 3b)}{(2a − b)}\)?
(1) \(\frac{−2a}{b − 2a}\)=8
(2) 6a – 3b = 3
(1) \(\frac{−2a}{b − 2a}\)=8
(2) 6a – 3b = 3
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shameekv1989
GMAT 3: 720 Q50 V38
Posts: 820
07 Feb 2020, 17:52
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What is the value of \(\frac{(2a+6a−3b)}{(2a−b)}\)?
(1) \(\frac{−2a}{b−2a}\)=8
(2) \(6a – 3b = 3\)
\(\frac{(2a+6a−3b)}{(2a−b)}\) = \(\frac{2a}{(2a−b)}\)+\(\frac{3(2a−b)}{(2a−b)}\) = \(\frac{(2a)}{(2a−b)}\)+3
i) \(\frac{−2a}{b−2a}\)=8 -> Sufficient as it gives me the value of \(\frac{2a}{2a-b}\)
ii) 2a-b = 1 (we don't know what 2a is though) - Not Sufficient
Answer - A
Why is OA C?
(1) \(\frac{−2a}{b−2a}\)=8
(2) \(6a – 3b = 3\)
\(\frac{(2a+6a−3b)}{(2a−b)}\) = \(\frac{2a}{(2a−b)}\)+\(\frac{3(2a−b)}{(2a−b)}\) = \(\frac{(2a)}{(2a−b)}\)+3
i) \(\frac{−2a}{b−2a}\)=8 -> Sufficient as it gives me the value of \(\frac{2a}{2a-b}\)
ii) 2a-b = 1 (we don't know what 2a is though) - Not Sufficient
Answer - A
Why is OA C?
globaldesi
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07 Feb 2020, 21:37
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(1) \(\frac{-2a}{b-2a} \)= 8
-2a = 8b-16a
14a =8b
7a = 4b
not sufficient
(2) 6a – 3b = 3
not sufficient
combine 1 and 2
and solve
sufficient
-2a = 8b-16a
14a =8b
7a = 4b
not sufficient
(2) 6a – 3b = 3
not sufficient
combine 1 and 2
and solve
sufficient
