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What is the value of h ? (1) h^2 = 36 (2) h^2 + 12h = -36

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What is the value of h ? (1) h^2 = 36 (2) h^2 + 12h = -36  [#permalink]

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New post Updated on: 17 Jul 2019, 23:52
1
5
00:00
A
B
C
D
E

Difficulty:

  5% (low)

Question Stats:

80% (00:44) correct 20% (01:02) wrong based on 189 sessions

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What is the value of h ?

(1) h^2 = 36
(2) h^2 + 12h = -36

Originally posted by A4G on 03 Dec 2013, 17:15.
Last edited by Bunuel on 17 Jul 2019, 23:52, edited 2 times in total.
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Re: What is the value of h ? (1) h^2 = 36 (2) h^2 + 12h = -36  [#permalink]

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New post 03 Dec 2013, 17:18
1
A4G wrote:
What is the value of h ?
(1) h^2 = 36
(2) h^2 + 12h = -36



Statement 1 :
h^2 = 36
h = +6 or h= -6
Not sufficient

Statement 2:
h^2 + 12h +36 = 0
(h+6)^2 = 0
h+6 = 0
h = -6
Sufficient .
Hence B
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Re: What is the value of h ? (1) h^2 = 36 (2) h^2 + 12h = -36  [#permalink]

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New post 12 May 2016, 00:21
A4G wrote:
What is the value of h ?

(1) h^2 = 36
(2) h^2 + 12h = -36



From statement 2,
(h+6)^2 = 0
h+6 = 0
h = -6, that is clearly sufficient. In this case, B is sufficient

But l approached the statement differently,
h (h+12) = -36
Hence, h=-36 or h = -48. Two values for h. Hence insufficient. In this case the answer would be E
l know it's a silly mistake. :oops: Could someone please clarify.

Regards,
Rana Azad
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Re: What is the value of h ? (1) h^2 = 36 (2) h^2 + 12h = -36  [#permalink]

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New post 12 May 2016, 00:36
1
ranaazad wrote:
A4G wrote:
What is the value of h ?

(1) h^2 = 36
(2) h^2 + 12h = -36



From statement 2,
(h+6)^2 = 0
h+6 = 0
h = -6, that is clearly sufficient. In this case, B is sufficient

But l approached the statement differently,
h (h+12) = -36
Hence, h=-36 or h = -48. Two values for h. Hence insufficient. In this case the answer would be E
l know it's a silly mistake. :oops: Could someone please clarify.

Regards,
Rana Azad


Hi Rana,
h (h+12) = -36 does not mean h =-36 or h=-48..
substitute and check..
h=-36......
h(h+12) = -36
so -36(-36+12) = -36.......... -36+12 = 1.. NO

h (h+12) = -36 does not mean h =-36
IT means the product of h and h+12 is -36...
so if h=-6, h+12 = -6+12 = 6...
and h*(h+12) = -6 * 6 = -36 ... correct..

Always take all to ONE side and solve
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Re: What is the value of h ? (1) h^2 = 36 (2) h^2 + 12h = -36  [#permalink]

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New post 12 May 2016, 00:45
chetan2u wrote:
ranaazad wrote:
A4G wrote:
What is the value of h ?

(1) h^2 = 36
(2) h^2 + 12h = -36



From statement 2,
(h+6)^2 = 0
h+6 = 0
h = -6, that is clearly sufficient. In this case, B is sufficient

But l approached the statement differently,
h (h+12) = -36
Hence, h=-36 or h = -48. Two values for h. Hence insufficient. In this case the answer would be E
l know it's a silly mistake. :oops: Could someone please clarify.

Regards,
Rana Azad


Hi Rana,
h (h+12) = -36 does not mean h =-36 or h=-48..
substitute and check..
h=-36......
h(h+12) = -36
so -36(-36+12) = -36.......... -36+12 = 1.. NO

h (h+12) = -36 does not mean h =-36
IT means the product of h and h+12 is -36...
so if h=-6, h+12 = -6+12 = 6...
and h*(h+12) = -6 * 6 = -36 ... correct..

Always take all to ONE side and solve


l understand now. Thank you very much, sir! :)
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Re: What is the value of h ? (1) h^2 = 36 (2) h^2 + 12h = -36  [#permalink]

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New post 17 Nov 2016, 20:21
Hi guys. I was struggling with the same question and I still do not understand your answers' explanations.
I agree that statement (1) is insufficient but I don't understand how statement (2) is sufficient. Here's how I did my calculations for statement (2):
h^2 + 12h = -36
h^2 + 12h + 36 = 0
h^2 + 12h + 6^2 = 0
(h + 6)^2 + 12h = 0
From here why does 12h disappear from the equation to make this statement sufficient ?
Thank you.

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Re: What is the value of h ? (1) h^2 = 36 (2) h^2 + 12h = -36  [#permalink]

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New post 17 Nov 2016, 23:12
Grid wrote:
Hi guys. I was struggling with the same question and I still do not understand your answers' explanations.
I agree that statement (1) is insufficient but I don't understand how statement (2) is sufficient. Here's how I did my calculations for statement (2):
h^2 + 12h = -36
h^2 + 12h + 36 = 0
h^2 + 12h + 6^2 = 0
(h + 6)^2 + 12h = 0
From here why does 12h disappear from the equation to make this statement sufficient ?
Thank you.

Posted from my mobile device


h^2 + 12h + 6^2 = 0 is the same as (h + 6)^2 = 0, so there is no extra "12h" there.
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Re: What is the value of h ? (1) h^2 = 36 (2) h^2 + 12h = -36  [#permalink]

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New post 29 Nov 2016, 16:32
1
A4G wrote:
What is the value of h ?

(1) h^2 = 36
(2) h^2 + 12h = -36


We need to determine the value of h.

Statement One Alone:

h^2 = 36

We can solve the equation as follows:

h^2 = 36

√(h^2) = √(36)

|h| = 6

h = 6 or h = -6

Since there are two different values for h, statement one alone is not sufficient to answer the question. We can eliminate answer choices A and D.

Statement Two Alone:

h^2 + 12h = -36

We can solve the equation as follows:

h^2 + 12h = -36

h^2 +12 h + 36 = 0

(h + 6)(h + 6) = 0

h = -6

Since there is only one value for h, statement two alone is sufficient to answer the question.

Answer: B
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Re: What is the value of h ? (1) h^2 = 36 (2) h^2 + 12h = -36  [#permalink]

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Re: What is the value of h ? (1) h^2 = 36 (2) h^2 + 12h = -36   [#permalink] 17 Nov 2019, 23:56
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