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yoovi4u
Joined: 23 Jan 2013
Last visit: 17 Feb 2016
Posts: 5
Given Kudos: 11
Concentration: Marketing, Organizational Behavior
Schools: Yale '17 Mays '17 (S) Kenan-Flagler '17 (S)
GMAT 1: 600 Q44 V28
GPA: 3.9
WE:Information Technology (Computer Software)
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
69% (01:18) correct
31%
(01:19)
wrong
based on 245
sessions
History
Date
Time
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What is the value of integer n?
(1) n = n^4
(2) 1^n ≠ n
I came across a question in Kaplan's 2014 review book. I am not too satisfied with the answer and explanation given. Please help me around here.
They explained saying B is right with the implication that the value of n = 0 will fit perfectly and no other possibility.
But I am confused and I think -1 will also be a valid candidate for the equation, making it an E-er.
What do you think?
Also, the Kaplan review problems seem to be fairly less complex. Does this reflect real GMAT?
P.S: I haven't taken any Kaplan CATs yet.
Thanks,
Yuvi
(1) n = n^4
(2) 1^n ≠ n
I came across a question in Kaplan's 2014 review book. I am not too satisfied with the answer and explanation given. Please help me around here.
Answer in Kaplan
They explained saying B is right with the implication that the value of n = 0 will fit perfectly and no other possibility.
But I am confused and I think -1 will also be a valid candidate for the equation, making it an E-er.
What do you think?
Also, the Kaplan review problems seem to be fairly less complex. Does this reflect real GMAT?
P.S: I haven't taken any Kaplan CATs yet.
Thanks,
Yuvi
09 Feb 2014, 05:17
Kudos
Bookmarks
B is clearly incorrect.
Stmt 2: 1^n != n.
if n=0 then 1^0 != 0
if n=2 then 1^2 != 2
if n=3 then 1^3 != 3 and so on hence n can ANY integer other than 1 & -1. Multiple values of n are possible. not sufficient.
Stmt 1: n = n^4
n can be 0 or 1. not sufficient.
(1)+(2) n can be only 0. hence C must be the answer.
On the other hand if statement 2 says 1^n = n. then n can only be 1 or -1. Again here also C will be the solution.
Stmt 2: 1^n != n.
if n=0 then 1^0 != 0
if n=2 then 1^2 != 2
if n=3 then 1^3 != 3 and so on hence n can ANY integer other than 1 & -1. Multiple values of n are possible. not sufficient.
Stmt 1: n = n^4
n can be 0 or 1. not sufficient.
(1)+(2) n can be only 0. hence C must be the answer.
On the other hand if statement 2 says 1^n = n. then n can only be 1 or -1. Again here also C will be the solution.
09 Feb 2014, 05:33
Kudos
Bookmarks
1^-1 is equal to 1 which is not equal to -1. But only 0 satisfies both statements.
Answer should be C
Sent from my iPhone using Tapatalk
Answer should be C
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