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What is the value of (n + 1)^2?

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What is the value of (n + 1)^2? [#permalink]

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New post 01 Jun 2016, 03:30
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Re: What is the value of (n + 1)^2? [#permalink]

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New post 01 Jun 2016, 04:06
1. n(n-6)=-9 --> n=3 or n=1 two distinct values ...insufficient !!
2. n2+1-2n-n2+5=0 2n-6=0 , n=3 sufficient !!

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Re: What is the value of (n + 1)^2? [#permalink]

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CounterSniper wrote:
1. n(n-6)=-9 --> n=3 or n=1 two distinct values ...insufficient !!
2. n2+1-2n-n2+5=0 2n-6=0 , n=3 sufficient !!

B


Hi,

n(n-6)=-9 means n= 3..... not n=1..

(1) \(n^2 - 6n = -9\)
\(n^2-6n=-9.............n^2-6n+9=0.............(n-3)^2 = 0................n=3\)

Statement 1 is suff...

(2) \((n-1)^2 = n^2 - 5\)
\(n^2-2n+1 =n^2-5................-2n+1=-5...............2n=5+1=6...............n=3\)

again suff

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Re: What is the value of (n + 1)^2? [#permalink]

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New post 15 Jun 2016, 14:45
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Bunuel wrote:
What is the value of (n + 1)²?

(1) n² - 6n = -9
(2) (n - 1)² = n² - 5


Target question: What is the value of (n + 1)²?

Statement 1: n² - 6n = -9
This is a quadratic equation, so let's set it equal to zero: n² - 6n + 9= 0
Factor to get: (n - 3)(n - 3) = 0
So, n = 3
Since we know that n has only one value (n= 3), we can easily determine the value of (n + 1)²
Since we can answer the target question with certainty, statement 1 is SUFFICIENT

Statement 2: (n - 1)² = n² - 5
Expand left side: n² - 2n + 1 = n² - 5
Subtract n² from both sides: -2n + 1 = -5
Subtract 1 from both sides: -2n = - 6
Solve: n = 3
Since we know that n has only one value (n= 3), we can easily determine the value of (n + 1)²
Since we can answer the target question with certainty, statement 2 is SUFFICIENT

Answer =
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Re: What is the value of (n + 1)^2? [#permalink]

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New post 21 Dec 2017, 18:13
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Re: What is the value of (n + 1)^2?   [#permalink] 21 Dec 2017, 18:13
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