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What is the value of x?

(1) 4x^2 - 4x + 1 = 0 --> recognize the square of the difference: \(4x^2 - 4x + 1 = (2x-1)^2=0\) --> \(2x-1=0\) --> \(x=\frac{1}{2}\). Sufficient.

(2) 4x^2 - 1 = 0 --> \(x^2=\frac{1}{4}\) --> \(x=\frac{1}{2}\) or \(x=-\frac{1}{2}\). Two different answers. Not sufficient.

Answer: A.
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What is the value of X?

1. 4.x^2-4.x+1=0
a=4, b=-4, and c=1. Use the quadratic formula: (-b +/- (Sqrt(b^2-4.a.c))/2a). Put the values and the discriminant, i.e. sqrt(b^2-4ac) becomes zero. This mean there is only 1 root which we don't have to calculate. SUFFICIENT

2. 4x^2-1=0
4x^2=1
x^2=(1/4)
x=sqrt(1/4)
x=1/2 OR -1/2 INSUFFICIENT

Therefore answer is A.
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