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20 Oct 2013, 06:32
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
60% (00:47) correct
40%
(00:43)
wrong
based on 2379
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20 Oct 2013, 06:36
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What is the value of x^2 - y^2?
\(x^2 - y^2=(x-y)(x+y)\)
(1) x + y = 2x --> re-arrange: \(x-y=0\) --> \((x-y)(x+y)=0\). Sufficient.
(2) x - y = 0 --> \(x-y=0\) --> \((x-y)(x+y)=0\). Sufficient.
Answer: D.
\(x^2 - y^2=(x-y)(x+y)\)
(1) x + y = 2x --> re-arrange: \(x-y=0\) --> \((x-y)(x+y)=0\). Sufficient.
(2) x - y = 0 --> \(x-y=0\) --> \((x-y)(x+y)=0\). Sufficient.
Answer: D.
29 May 2014, 03:26
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(1) x+y=2x
We know that x+x=2x, so it is obvious that x=y and x^2-y^2=0
SUFFICIENT
(2) x-y=0
Rearranging this, we get x=y, so again x^2-y^2=0
SUFFICIENT
Answer is D
Posted from my mobile device
We know that x+x=2x, so it is obvious that x=y and x^2-y^2=0
SUFFICIENT
(2) x-y=0
Rearranging this, we get x=y, so again x^2-y^2=0
SUFFICIENT
Answer is D
Posted from my mobile device
