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A
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Difficulty:
55%
(hard)
Question Stats:
50% (01:14) correct
50%
(01:13)
wrong
based on 18
sessions
History
Date
Time
Result
Not Attempted Yet
What is the value of |x-7| + |x+8|?
\(A. x^2 < 25\)
\(B. x^2 > 36\)
\(A. x^2 < 25\)
\(B. x^2 > 36\)
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WiziusCareers1
Joined: 27 Apr 2009
Last visit: 24 Apr 2026
Posts: 178
Given Kudos: 35
Status:Not Applying
Location: India
Schools: HBS '14 (A)
GMAT 1: 730 Q51 V36
10 Jul 2019, 22:15
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Considering statement (1) alone:
x^2 < 25
=> -5 < x < 5
Let x = -4
=> |x - 7| + |x + 8| = |-4 - 7| + |-4 + 8| = 11 + 4 = 15
Let x = 0
=> |x - 7| + |x + 8| = |0 - 7| + |0 + 8| = 7 + 8 = 15
Let x = 4
=> |x - 7| + |x + 8| = |4 - 7| + |4 + 8| = 3 + 12 = 15
Hence, SUFFICIENT
Considering statement (2) alone:
x^2 > 36
=> x > 6 and x < -6
Let x = 7
=> |x - 7| + |x + 8| = |7 - 7| + |7 + 8| = 0 + 15 = 15
Let x = 10
=> |x - 7| + |x + 8| = |10 - 7| + |10 + 8| = 3 + 18 = 21
Hence, INSUFFICIENT
The answer is (A).
x^2 < 25
=> -5 < x < 5
Let x = -4
=> |x - 7| + |x + 8| = |-4 - 7| + |-4 + 8| = 11 + 4 = 15
Let x = 0
=> |x - 7| + |x + 8| = |0 - 7| + |0 + 8| = 7 + 8 = 15
Let x = 4
=> |x - 7| + |x + 8| = |4 - 7| + |4 + 8| = 3 + 12 = 15
Hence, SUFFICIENT
Considering statement (2) alone:
x^2 > 36
=> x > 6 and x < -6
Let x = 7
=> |x - 7| + |x + 8| = |7 - 7| + |7 + 8| = 0 + 15 = 15
Let x = 10
=> |x - 7| + |x + 8| = |10 - 7| + |10 + 8| = 3 + 18 = 21
Hence, INSUFFICIENT
The answer is (A).
firas92
Current Student
Joined: 16 Jan 2019
Last visit: 02 Dec 2024
Posts: 616
Own Kudos:
Given Kudos: 142
Location: India
Concentration: General Management
Schools: Tepper '23 (M$) Foster '23 (D)
GMAT 1: 740 Q50 V40
WE:Sales (Other)
Products:
10 Jul 2019, 22:34
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All values within the range -8 ≤ x ≤ 7 will give the same unique solution
1) |x|<5 or -5<x<5
Thus x always lies within the range -8 ≤ x ≤ 7
Sufficient
2) |x|>6
This means x<-6 or x>6
So, x may or may not be within the range -8 ≤ x ≤ 7
Insufficient
Answer is (A)
1) |x|<5 or -5<x<5
Thus x always lies within the range -8 ≤ x ≤ 7
Sufficient
2) |x|>6
This means x<-6 or x>6
So, x may or may not be within the range -8 ≤ x ≤ 7
Insufficient
Answer is (A)
