When 102 is divided by x, the remainder is 2. What is the smallest pos

Question

When 102 is divided by x, the remainder is 2. What is the smallest positive integer value of x?

A. 4
B. 6
C. 8
D. 10
E. 20

GMATinsight · Answer

102 divided by x leaves remainder 2

i.e. 102-2 = 100 is divisible by x

x = Smallest factor of 100 Greater than 2

factors = of 100 are {1, 2, 4, 5, ...}

Smallest factors of 100 greater than 2 = 4

ANswer: Option A

yashikaaggarwal · Answer

Bunuel  4 is leaving remainder 2 as well, can you explain why answer is 10?

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Bunuel · Answer

The OA is A. Edited.

RaghavKhanna · Answer

102 = xq + 2
xq = 100

Of the available options, x = 4 satisfies the requirement.

Answer: A

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