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# When an object is dropped, the number of feet N that it

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Senior Manager
Joined: 08 Aug 2005
Posts: 251

Kudos [?]: 60 [0], given: 0

When an object is dropped, the number of feet N that it [#permalink]

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27 Apr 2006, 23:34
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When an object is dropped, the number of feet N that it falls is given by the formula N=1/2 gt^2, where t is the time in seconds since it was dropped and g is 32.2, if it takes 5 seconds for the object to reach the ground, how many feet does it fall?

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Manager
Joined: 20 Mar 2005
Posts: 201

Kudos [?]: 16 [0], given: 0

Location: Colombia, South America

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28 Apr 2006, 00:11
getzgetzu wrote:
When an object is dropped, the number of feet N that it falls is given by the formula N=1/2 gt^2, where t is the time in seconds since it was dropped and g is 32.2, if it takes 5 seconds for the object to reach the ground, how many feet does it fall?

isn't just

N= 1/2*32.2*(5^2)

N= 16.1*25 = 402.5

Kudos [?]: 16 [0], given: 0

Manager
Joined: 20 Mar 2005
Posts: 201

Kudos [?]: 16 [0], given: 0

Location: Colombia, South America

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28 Apr 2006, 02:22
getzgetzu wrote:
The OA is 144.9

could you double check your question, isn't 5 seconds or 3 seconds?

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VP
Joined: 29 Apr 2003
Posts: 1403

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28 Apr 2006, 02:39
I get 402.5 also!! How did u get 144.9! Unless probabaly the object is thrown up! Then the kinematics shud be different!

U need to break it up into two sections and then compute!

Kudos [?]: 29 [0], given: 0

28 Apr 2006, 02:39
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