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02 Jun 2021, 07:15
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Difficulty:
35%
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Question Stats:
68% (01:25) correct
32%
(01:39)
wrong
based on 111
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Which of the following equations has no solutions for x?
A. \(x^2+8x=-17\)
B. \(x^2+8x=-13\)
C. \(x^2+8x=0\)
D. \(x^2+8x=1\)
E. \(x^2+8x=16\)
A. \(x^2+8x=-17\)
B. \(x^2+8x=-13\)
C. \(x^2+8x=0\)
D. \(x^2+8x=1\)
E. \(x^2+8x=16\)
02 Jun 2021, 07:34
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Quadratic formula (-b±√(b²-4ac))/(2a) where a, b and c are from the equation ax^2 + bx + c = 0
When (b²-4ac) in the formula is a negative number, then we will have complex number, or in this case no solution for x.
As all of the answer choices have 8 as b, we want a number for c when multiplied by 4 is greater than 8^2 (64)
A - 17*4 = 68
Answer A
When (b²-4ac) in the formula is a negative number, then we will have complex number, or in this case no solution for x.
As all of the answer choices have 8 as b, we want a number for c when multiplied by 4 is greater than 8^2 (64)
A - 17*4 = 68
Answer A
02 Jun 2021, 12:44
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If you get a negative value inside the square root, then there will be no real number solution, and therefore no x-intercepts. In other words, if the the discriminant (the expression b2 – 4ac) has a value which is negative, then you won't have any graphable zeroes.
Option A satisfies the condition.
Option A satisfies the condition.
