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Updated on: 28 Jun 2017, 21:17
Originally posted by inakihernandez on 02 Oct 2016, 09:52.
Last edited by Bunuel on 28 Jun 2017, 21:17, edited 1 time in total.
Last edited by Bunuel on 28 Jun 2017, 21:17, edited 1 time in total.
Edited the question.
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
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(medium)
Question Stats:
68% (01:40) correct
32%
(01:53)
wrong
based on 154
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Which of the following equations is NOT equivalent to 4a^2 = 16b^2 + 49?
(A) \(\frac{16b^2+49}{4}= a^2\)
(B) \(\frac{(2a-7)(2a+7)}{16}=b^2\)
(C) \(2a-4b=7\)
(D) \(8a^2 - 32b^2=98\)
(E) \(4(a-2b)(a+2b)=49\)
(A) \(\frac{16b^2+49}{4}= a^2\)
(B) \(\frac{(2a-7)(2a+7)}{16}=b^2\)
(C) \(2a-4b=7\)
(D) \(8a^2 - 32b^2=98\)
(E) \(4(a-2b)(a+2b)=49\)
02 Oct 2016, 09:57
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inakihernandez
Which of the following equations is NOT equivalent to 4a^2 = 16b^2 + 49?
(A) 16b^2+49/4= a^2
(B) (2a-7)(2a+7)/16=b^2
(C) 2a-4b=7
(D) 8a^2 - 32b^2=98
(E) 4(a-2b)(a+2b)=49
(A) 16b^2+49/4= a^2
(B) (2a-7)(2a+7)/16=b^2
(C) 2a-4b=7
(D) 8a^2 - 32b^2=98
(E) 4(a-2b)(a+2b)=49
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Hope it helps.
28 Jun 2017, 19:24
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Hi,
Any admin/mod could please fix the typos in this question? Bunuel
There are actually 2 correct answers (A) and (C)
Which of the following equations is NOT equivalent to 4a^2 = 16b^2 + 49?
(A) 16b^2+49/4= a^2
(C) 2a-4b=7
Based on the posted OA as (C), adjustment should be made on (A) as follows: (A) 4b^2+49/4= a^2, so that (A) would become equivalent to 4a^2 = 16b^2 + 49
Please fix it so that users will not be confused.. Thanks.
Any admin/mod could please fix the typos in this question? Bunuel
There are actually 2 correct answers (A) and (C)
Which of the following equations is NOT equivalent to 4a^2 = 16b^2 + 49?
(A) 16b^2+49/4= a^2
(C) 2a-4b=7
Based on the posted OA as (C), adjustment should be made on (A) as follows: (A) 4b^2+49/4= a^2, so that (A) would become equivalent to 4a^2 = 16b^2 + 49
Please fix it so that users will not be confused.. Thanks.
