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Hi,

Any admin/mod could please fix the typos in this question? Bunuel

There are actually 2 correct answers (A) and (C)

Which of the following equations is NOT equivalent to 4a^2 = 16b^2 + 49?

(A) 16b^2+49/4= a^2

(C) 2a-4b=7

Based on the posted OA as (C), adjustment should be made on (A) as follows: (A) 4b^2+49/4= a^2, so that (A) would become equivalent to 4a^2 = 16b^2 + 49

Please fix it so that users will not be confused.. Thanks.

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Edited. Thank you.
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Which of the following equations is NOT equivalent to \(4a^2 = 16b^2 + 49\)?


\(4a^2 = 16b^2 + 49\)=
\(4a^2-16b^2=49\)

(A) \(\frac{16b^2+49}{4}= a^2\)
Rearranging the equation gives this answer

(B) \(\frac{(2a-7)(2a+7)}{16}=b^2\)
The equation can be rewriiten in th form of (a+b) * (a-b)
\(4a^2-49=16b^2\)
\((2a+7)(2a-7)=16b^2\)

(C) \(2a-4b=7\)
This is not achievable even after solving

(D) \(8a^2 - 32b^2=98\)
This equation is multiplied by 2 from the original equation

(E) \(4(a-2b)(a+2b)=49\)[/quote]
\(4a^2-16b^2= 49\)
\(4(a^2-4b^2)=49\)
The equation can be rewriiten in th form of (a+b) * (a-b)

Option C is not possible
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