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Which of the following integers represents a sum of 3 consecutive even integers?

A. 200
B. 303
C. 400
D. 554
E. 570

I'm ashamed to say that I don't understand this. This question came from the flashcards from GMATclub.




I figured I'd just list out the possible integers that can occupy the ones place: 0, 2, 4, 6, 8 and add any three consecutively to see what answer matched any of the answer choices' ones place.

0+2+4 = 6
2+4+6 = 12
4+6+8 = 18
6+8+0 = 14

I wanted to say the answer is D but they said the answer was E.

Sum of three consecutive Even Integers must be a multiple of 2 as well as a multiple of 3 because such a sum is always 3 times the middle number (applicable to all equally spaced numbers)

Divisibility of 3: Sum of the digits of the number must be divisible by 3
Divisibility of 2: Unit digit of the number must be divisible by 2


A. 200 NOT A MULTIPLE OF 3 SO RULED OUT
B. 303 NOT A MULTIPLE OF 2 SO RULED OUT
C. 400 NOT A MULTIPLE OF 3 SO RULED OUT
D. 554 NOT A MULTIPLE OF 3 SO RULED OUT
E. 570 A MULTIPLE OF BOTH 2 AND 3 SO THE CORRECT ANSWER!!!

I didn't even think of that. So with that we know the three consecutive even integers are.

188 190 192

Thank you.
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BassanioGratiano
Which of the following integers represents a sum of 3 consecutive even integers?

A. 200
B. 303
C. 400
D. 554
E. 570

I'm ashamed to say that I don't understand this. This question came from the flashcards from GMATclub.




I figured I'd just list out the possible integers that can occupy the ones place: 0, 2, 4, 6, 8 and add any three consecutively to see what answer matched any of the answer choices' ones place.

0+2+4 = 6
2+4+6 = 12
4+6+8 = 18
6+8+0 = 14

I wanted to say the answer is D but they said the answer was E.

Another approach to solve this question is as follows:

Let the 3 consecutive even numbers be x-2, x and x+2.

=> Their sum = x-2+x+x+2 = 3x

Now considering that 3 is divides the sum perfectly and the quotient would be an even number, only 570 qualifies as an answer.
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We know that even+even= even, therefore option B is ruled out at first.

Now we take the first even integer to be 2x(we are taking 2x because any integer multiplied by 2 will give an even integer), therefore the following consecutive integers would be 2x+2 & 2x+4

the sum of the consecutive integers = 2x + (2x+2) + (2x+4) = 6x+6 = 6(x+1)

6(x+1)= even integer
the number has to be a multiple of either 6 or (x+1)

Now we need to look at the answer options and see which number is divisible by 6.
For a number to be a multiple of 6 it has to be a multiple of both 2 & 3.
Hence Ans is E
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Three consecutive even integers can be written as: x-2 +x + x+2. This leads to sum being 3x i.e. it is a factor of 3. 303 is divisible by 3 however it results in an odd number as x=101. Rest are not divisible by 3. 570 is divisible by 3 and results in x being 190.
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