EgmatQuantExpert wrote:
The figure above shows the railway tracks between three cities A, B and C. The distance between city A and city B is 100 kilometres and city A and city C is 240 kilometres. A train can travel from city A to city B via city C only and vice versa. Two trains are scheduled to start from city A and city B respectively at 9 AM and travel to city B and city A respectively. The speeds of the train starting from city A and city B are 20 kilometres per hour and 25 kilometres per hour respectively. If the train from city A starts half an hour early and the train from city B starts half an hour late, at what time will the two trains meet?
A. 7:10 PM
B. 8:10 PM
C. 8:23 PM
D. 8:40 PM
E. 8:53 PM
Thanks,
Saquib
Quant Expert
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length of BC =260(right triangle properties)
distance between A to B via c =240+260= 500km
Since a train leaves 1/2hr early and another 1/2hr late ,we can combined say first train leave 1 hr early ie 8:00 AM
distance travelled by first train in this 1 hr =40km
thus they meet on time =distance between them /relative speed
=(500-20)/(20+25)= 10.66
thus they meet after 10hrs 40 mints after starting
09:30 AM +10hrs 40 mints = 8:10PM
Ans B