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Working alone, A can complete a task in ‘a’ days and B in ‘b’ days. Th

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Working alone, A can complete a task in ‘a’ days and B in ‘b’ days. Th [#permalink]

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New post 29 Jan 2016, 03:20
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Working alone, A can complete a task in ‘a’ days and B in ‘b’ days. They take turns in doing the task with each working 2 days at a time. If A starts they finish the task in exactly 10 days. If B starts, they take half a day more. How long does it take to complete the task if they both work together?

A. 46/9
B. 50/9
C. 50/11
D. 36/7
E. 210/41

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Working alone, A can complete a task in ‘a’ days and B in ‘b’ days. Th [#permalink]

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New post 29 Jan 2016, 10:20
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Bunuel wrote:
Working alone, A can complete a task in ‘a’ days and B in ‘b’ days. They take turns in doing the task with each working 2 days at a time. If A starts they finish the task in exactly 10 days. If B starts, they take half a day more. How long does it take to complete the task if they both work together?

A. 46/9
B. 50/9
C. 50/11
D. 36/7
E. 210/41


Hi,

firstly it is a tough Q..
if one is clueless where to start, we can work on the info and easily eliminate three choices B,C, and D, and E too can be eliminated after a bit of thought...

IN first case A working for 6 days and B for 4 days, work is completed and in second case A for 4.5 days and B for 6 days, wk gets completed..
so if we combine A for 10.5 days and B for 10 , wk can be completed twice ...
so wk to be completed once, A requires to work for 5.25 days and B for 5 days...

what can we make out ..

1) if both A and B work for 5 days, the work will not be completed, as we have to add .25 day work of B to it.. C (50/11)<5 is out...

2) work will be completed before (5+5.25)/2 days, as work of .25 days of A is being done by both together and A is faster than B..
so total time will be greater than 5.125 and should be less than 5.25, when A is faster than B ..
so following can be eliminated
A 46/9=5.111 <5.125
B 50/9=5.55>5.25

E 210/41= 5.122<5.125..

D 36/7=5.14...CORRECT .. between 5.125 and 5.25 is the answer..



answer can also be arrived at by proper work-time method.
IN first case A working for 6 days and B for 4 days, work is completed
or 6/a +4/b=1..(i)

and in second case A for 4.5 days and B for 6 days, wk gets completed..
so 4.5/a+ 6/b=1..(ii)

or 6/a +4/b= 4.5/a+ 6/b...
we get a=3b/4 here ..
substitute this value in (i)..
24/3b +4/b=1...
this will give us b as 12..
so a= 3b/4=9..

we have to find 1/a+1/b as one day work of both..
1/12 + 1/9= (3+4)/36= 7/36..
so time taken = 36/7
D
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Working alone, A can complete a task in ‘a’ days and B in ‘b’ days. Th [#permalink]

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New post 31 Jan 2016, 08:27
Bunuel wrote:
Working alone, A can complete a task in ‘a’ days and B in ‘b’ days. They take turns in doing the task with each working 2 days at a time. If A starts they finish the task in exactly 10 days. If B starts, they take half a day more. How long does it take to complete the task if they both work together?

A. 46/9
B. 50/9
C. 50/11
D. 36/7
E. 210/41


hi Bunuel,
THanks for such a lovely Q.. Edited
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Re: Working alone, A can complete a task in ‘a’ days and B in ‘b’ days. Th [#permalink]

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New post 31 Jan 2016, 11:16
chetan2u wrote:
Bunuel wrote:
Working alone, A can complete a task in ‘a’ days and B in ‘b’ days. They take turns in doing the task with each working 2 days at a time. If A starts they finish the task in exactly 10 days. If B starts, they take half a day more. How long does it take to complete the task if they both work together?

A. 46/9
B. 50/9
C. 50/11
D. 36/7
E. 210/41


Hi,

firstly it is a tough Q..
if one is clueless where to start, we can work on the info and easily eliminate three choices B,C, and D, and E too can be eliminated after a bit of thought...

IN first case A working for 6 days and B for 4 days, work is completed and in second case A for 4 days and B for 13/2 days, wk gets completed..
so if we combine A for 10 days and B for 10 and 1/2 day, wk can be completed twice ...
so wk to be completed once, A requires to work for 5 days and B for 5.25 days...

what can we make out ..

1) if both A and B work for 5 days, the work will not be completed, as we have to add .25 day work of B to it.. C (50/11)<5 is out...

2) work will be completed before (5+5.25)/2 days, as work of .25 days of B is being done by both together and A is faster than B..
so total time will be equal to 5.125 and should be less than 5.12, when A is faster than ..
so following can be eliminated
B 50/9=5.55>5.12
D 36/7=5.14>5.125
E 210/41= 5.122>5.12..

A 46/9=5.111 <5.12 is the answer..



answer can also be arrived at by proper work-time method.
IN first case A working for 6 days and B for 4 days, work is completed
or 6/a +4/b=1..(i)

and in second case A for 4 days and B for 13/2 days, wk gets completed..
so 4/a+ 6.5/b=1..(ii)


or 6/a +4/b= 4/a+ 6.5/b...
we get a=4b/5 here ..E which the closest to the answer can be eliminated easily in POE when we know this relation
substitute this value in (i)..
30/4b +4/b=1...
this will give us b as 11.5..
so a= 4b/5=9.2..

we have to find 1/a+1/b as one day work of both..
1/11.5 + 1/9.2= 20.7/105.8= 9/46..
so time taken = 46/9
A


The answer is given as D. I think you should check the highlighted part.
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Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


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Re: Working alone, A can complete a task in ‘a’ days and B in ‘b’ days. Th [#permalink]

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New post 31 Jan 2016, 15:51
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A can complete 1/a of the task daily
B can complete 1/b of the task daily

By the two statements (starting with A they complete the task in 10 days and starting with B they complete in 10,5 days), we have:
I. 6/a + 4/b = 1
II. 6/b + 4,5/a = 1

=> 6/a + 4/b = 6/b + 4,5/a => (6b + 4a)/ab = (6a + 4,5b)/ab => 2a = 1,5b => b = 4a/3 (III)

Substituting it in the equation 1: 6/a + 4/(4a/3) = 1 => 6/a + 3/a = 1 => 9/a = 1 => a = 9
Substituting it in the equation III again: b = 4*9/3 => b = 12

Considering the values of A and B, they would be able to complete 1/9 + 1/12 = 7/36 of the task daily, so they would take 36/7 days to complete the task.

Answer: D
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Re: Working alone, A can complete a task in ‘a’ days and B in ‘b’ days. Th [#permalink]

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New post 31 Jan 2016, 19:36
Answer is (D)
A does 1/a part in 1 day =2/a part in 2 days
Similarly B does 2/b part is 2 days
When A starts
2/a+2/b+2/a+2/b+2/a=1 => 6/a+4/b=1 .....................(1)

When B starts
2/b+2/a+2/b+2/a+2/b+1/2a(Half days work) =1 => 2/b=3/2a ..................(2)

Solving (1) and (2)
we get a=9 and b = 12

A and B together does the work in ab/a+b =108/21 =36/7 days

Hence Answer is (D)
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Re: Working alone, A can complete a task in ‘a’ days and B in ‘b’ days. Th [#permalink]

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New post 22 Feb 2016, 18:04
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equation1: 6/a+4/b=1
equation2: 9/a+12/b=2
solving, a=9;b=12
let d=days for A and B to complete task working together
d(1/9+1/12)=1
d(7/36)=1
d=36/7 days
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Re: Working alone, A can complete a task in ‘a’ days and B in ‘b’ days [#permalink]

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New post 17 Mar 2016, 06:18
So I started and got the following equation, would love to get help on where I have gone wrong
6/a + 4/b = 1/10
That is 6 * 1/a (rate of A) and 4 * 1/b (rate of B) = 1/ 10 (overall time utilised)

second equation followed the same route, is my equation wrong??
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Re: Working alone, A can complete a task in ‘a’ days and B in ‘b’ days. Th [#permalink]

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New post 17 Mar 2016, 07:53
3
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Bunuel wrote:
Working alone, A can complete a task in ‘a’ days and B in ‘b’ days. They take turns in doing the task with each working 2 days at a time. If A starts they finish the task in exactly 10 days. If B starts, they take half a day more. How long does it take to complete the task if they both work together?

A. 46/9
B. 50/9
C. 50/11
D. 36/7
E. 210/41


When A starts, A works for 6 days and B for 4 days to complete the work.
6/a + 4/b = 1 Work

When B starts, A works for 4.5 days and B for 6 days to complete the work.
4.5/a + 6/b = 1 Work

Solving these two equations simultaneously, we get:
18/a + 12/b = 3
9/a + 12/b = 2
9/a = 1
a = 9
b = 12

Rate of work while working together = 1/9 + 1/12 = 7/36
Time taken to complete the work = 36/7 days
Answer (D)
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Re: Working alone, A can complete a task in ‘a’ days and B in ‘b’ days. Th [#permalink]

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New post 17 Mar 2016, 09:15
1
Bunuel wrote:
Working alone, A can complete a task in ‘a’ days and B in ‘b’ days. They take turns in doing the task with each working 2 days at a time. If A starts they finish the task in exactly 10 days. If B starts, they take half a day more. How long does it take to complete the task if they both work together?

A. 46/9
B. 50/9
C. 50/11
D. 36/7
E. 210/41

Let their efficiency ratio be a:b
Therefore, 6*a+4*b=4.5*a+6*b
=>a to b is 4:3
Number of days taken will be 3*k and 4*k, where k is a constant.
If they work together they take (3*k)*(4*k)/3*k+4*k = 12*k^2/7*k = 12*k/7
Look at the option. Only D could be the correct one.
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Re: Working alone, A can complete a task in ‘a’ days and B in ‘b’ days. Th [#permalink]

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Re: Working alone, A can complete a task in ‘a’ days and B in ‘b’ days. Th   [#permalink] 05 May 2018, 02:31
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