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Bunuel do we have practice questions for these types of simplifying square root problems in varying difficulty?
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Jake7Wimmer
Bunuel do we have practice questions for these types of simplifying square root problems in varying difficulty?
­
Check question involving rationalization of a fraction:

8. Exponents and Roots of Numbers



Check below for more:
ALL YOU NEED FOR QUANT ! ! !
Ultimate GMAT Quantitative Megathread

Hope it helps.­­­­
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\(\frac{1}{\sqrt{2}}/\sqrt{\frac{3}{2}}\) = \(\frac{1}{\sqrt{2}}*\frac{\sqrt{2}}{\sqrt{3}}\) = \(\frac{1}{\sqrt{3}}\) = \(\frac{1}{\sqrt{3}}*\frac{\sqrt{3}}{\sqrt{3}}\) = \(\frac{\sqrt{3}}{3}\)

Answer B.
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I understand that squaring the numerator and denominator is wrong. NBut I don't get why? Can anyone explain
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Ilanchezhiyan
I understand that squaring the numerator and denominator is wrong. NBut I don't get why? Can anyone explain

\(\frac{\frac{1}{\sqrt{2} } }{\sqrt{\frac{3}{2} } }\)

A. \(\frac{1}{3}\)

B. \(\frac{\sqrt{3} }{3}\)

C. \(\frac{\sqrt{3} }{2}\)

D. \(\frac{2\sqrt{3} }{3}\)

E. \(\sqrt{3}\)

You can solve this question by squaring. However, since we need the exact value from the options, we also need to square the options to see which one matches the result we get by squaring the expression.

\((\frac{\frac{1}{\sqrt{2}}}{\sqrt{\frac{3}{2}}})^2=\frac{\frac{1}{2}}{\frac{3}{2}}=\frac{1}{3}\)

So we need the option whose square is \(\frac{1}{3}\).

Option B is \(\frac{\sqrt{3} }{3}\), and:

\((\frac{\sqrt{3} }{3})^2 = \frac{3}{9} = \frac{1}{3}\)

Answer: B.
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Thanks Bunuel, Got it!
Bunuel


\(\frac{\frac{1}{\sqrt{2} } }{\sqrt{\frac{3}{2} } }\)

A. \(\frac{1}{3}\)

B. \(\frac{\sqrt{3} }{3}\)

C. \(\frac{\sqrt{3} }{2}\)

D. \(\frac{2\sqrt{3} }{3}\)

E. \(\sqrt{3}\)

You can solve this question by squaring. However, since we need the exact value from the options, we also need to square the options to see which one matches the result we get by squaring the expression.

\((\frac{\frac{1}{\sqrt{2}}}{\sqrt{\frac{3}{2}}})^2=\frac{\frac{1}{2}}{\frac{3}{2}}=\frac{1}{3}\)

So we need the option whose square is \(\frac{1}{3}\).

Option B is \(\frac{\sqrt{3} }{3}\), and:

\((\frac{\sqrt{3} }{3})^2 = \frac{3}{9} = \frac{1}{3}\)

Answer: B.
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