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21 Nov 2013, 02:03
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D
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Difficulty:
5%
(low)
Question Stats:
82% (00:59) correct
18%
(01:48)
wrong
based on 234
sessions
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Not Attempted Yet
If x is positive, then \(\frac{1}{\sqrt{x+1}+\sqrt{x}}=\)
A) 1
B) x
C) \(\frac{1}{x}\)
D) \(\sqrt{x+1}-\sqrt{x}\)
E) \(\sqrt{x+1}+\sqrt{x}\)
A) 1
B) x
C) \(\frac{1}{x}\)
D) \(\sqrt{x+1}-\sqrt{x}\)
E) \(\sqrt{x+1}+\sqrt{x}\)
21 Nov 2013, 02:11
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registerincog
Rationalize the fraction by multiplying it by \(\frac{\sqrt{x+1}-\sqrt{x}}{\sqrt{x+1}-\sqrt{x}}\) and apply \((a+b)(a-b)=a^2-b^2\) to the denominator:
\(\frac{1}{\sqrt{x+1}+\sqrt{x}}*\frac{\sqrt{x+1}-\sqrt{x}}{\sqrt{x+1}-\sqrt{x}}=\frac{\sqrt{x+1}-\sqrt{x}}{x+1-x}=\sqrt{x+1}-\sqrt{x}\).
Answer: D.
18 Dec 2013, 05:42
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Am I being stupid, or is the question missing something?
I.e. should there not be a question mark or something at the end, or at least an equal sign.
I.e. should there not be a question mark or something at the end, or at least an equal sign.
