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16 Dec 2025, 09:00
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
83% (02:37) correct
17%
(02:38)
wrong
based on 283
sessions
History
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Time
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A mountain climber is 10 kilometers from the summit and carries 25 oxygen canisters. The climber can climb at one of two constant paces. At the slower pace, the climber gains 4 kilometers per hour and uses 2 oxygen canisters per kilometer. At the faster pace, the climber gains 5 kilometers per hour but uses 30 percent more oxygen to climb any given distance than at the slower pace. Along the route, there is a single stopping point where the climber may pick up extra canisters. Stopping there always adds exactly 25 minutes to the total climb time, regardless of how many canisters are taken. The climber must choose either the slower pace or the faster pace and maintain that pace for the entire climb. What is the minimum possible time, in minutes, needed for the climber to reach the summit?
A. 120 minutes
B. 140 minutes
C. 145 minutes
D. 150 minutes
E. 175 minutes
M46-04
A. 120 minutes
B. 140 minutes
C. 145 minutes
D. 150 minutes
E. 175 minutes
M46-04
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16 Dec 2025, 10:00
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GMAT Club Official Explanation:
Case 1: Slower pace
Speed = 4 km/hour
Time = 10 km/4 = 2.5 hours = 150 minutes
Oxygen use = 2 canisters per km
Total needed = 10 * 2 = 20 canisters
He has 25, so no stop needed
Total time = 150 minutes
Case 2: Faster pace
Speed = 5 km/hour
Time = 10 km/5 = 2 hours = 120 minutes
Oxygen use = 30 percent more than 2, so 2.6 canisters per km
Total needed = 10 * 2.6 = 26 canisters
He has only 25, so he must stop
Stop adds 25 minutes
Total time = 120 + 25 = 145 minutes
Answer: C.
General Discussion
16 Dec 2025, 09:10
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Bunuel
Deconstructing the Question
Target: Find the minimum time to reach the summit.
Distance: 10 km.
Initial Oxygen Supply: 25 canisters.
Constraint: If required oxygen > 25, we must stop (adding 25 mins).
We need to compare the two scenarios (Slower Pace vs. Faster Pace).
Scenario 1: Slower Pace
Speed: 4 km/h.
Oxygen Usage: 2 canisters/km.
1. Calculate Time: \(Time = \frac{Distance}{Speed} = \frac{10}{4} = 2.5\) hours. Convert to minutes: \(2.5 \times 60 = 150\) minutes.
2. Check Oxygen: \(Total Oxygen = 10 \text{ km} \times 2 \text{ cans/km} = 20\) canisters. Since \(20 < 25\), we have enough oxygen. No stop needed.
Total Time (Slower): 150 minutes.
Scenario 2: Faster Pace
Speed: 5 km/h.
Oxygen Usage: 30% more than the slower pace per km.
1. Calculate Time: \(Time = \frac{Distance}{Speed} = \frac{10}{5} = 2\) hours. Convert to minutes: \(2 \times 60 = 120\) minutes.
2. Check Oxygen: Base usage = 2 cans/km. New usage = \(2 \times 1.30 = 2.6\) cans/km. \(Total Oxygen = 10 \text{ km} \times 2.6 \text{ cans/km} = 26\) canisters.
CRITICAL ISSUE: We need 26 canisters but only have 25. We are forced to stop to pick up extra canisters. Penalty: Add 25 minutes.
3. Calculate Total Time: \(Total = 120 \text{ (climb)} + 25 \text{ (stop)} = 145\) minutes.
Total Time (Faster): 145 minutes.
Conclusion Compare the two outcomes: Slower: 150 mins. Faster: 145 mins. The minimum possible time is 145 minutes.
Answer: C
