Information Given:
- The number of $0.25 coins is 8, so the total value of these coins is: 8×0.25=2 dollars8 \times 0.25 = 2 \text{ dollars}8×0.25=2 dollars
- The number of $0.50 coins is 4, so the total value of these coins is: 4×0.50=2 dollars4 \times 0.50 = 2 \text{ dollars}4×0.50=2 dollars
- Let the number of $1 coins be xxx. Therefore, the total value of $1 coins is: 1×x=x dollars1 \times x = x \text{ dollars}1×x=x dollars
Thus, the total value of all the coins is:
2+2+x=4+x dollars2 + 2 + x = 4 + x \text{ dollars}2+2+x=4+x dollars
The total number of coins is:
8+4+x=12+x coins8 + 4 + x = 12 + x \text{ coins}8+4+x=12+x coins
Statement (1):
The total value of the $1 coins is 50% of the total value of all the coins.
This translates to the equation:
x=0.5×(4+x)x = 0.5 \times (4 + x)x=0.5×(4+x)
Solving for xxx:
x=0.5×(4+x)x = 0.5 \times (4 + x)x=0.5×(4+x) x=2+0.5xx = 2 + 0.5xx=2+0.5x x−0.5x=2x - 0.5x = 2x−0.5x=2 0.5x=20.5x = 20.5x=2 x=4x = 4x=4
Thus, from Statement (1), we find that Warren has 4 $1 coins.
Statement (2):
The $1 coins make up 25% of the total number of coins.
This translates to the equation:
x=0.25×(12+x)x = 0.25 \times (12 + x)x=0.25×(12+x)
Solving for xxx:
x=0.25×(12+x)x = 0.25 \times (12 + x)x=0.25×(12+x) x=3+0.25xx = 3 + 0.25xx=3+0.25x x−0.25x=3x - 0.25x = 3x−0.25x=3 0.75x=30.75x = 30.75x=3 x=4x = 4x=4
Thus, from Statement (2), we also find that Warren has 4 $1 coins.
Conclusion:
Both statements (1) and (2) independently lead to the conclusion that Warren has 4 $1 coins. Therefore, the answer is
D: Each statement alone is sufficient to answer the question.
Bunuel
12 Days of Christmas 2024 - 2025 Competition with $40,000 of PrizesWarren has exactly three types of coins in his piggy bank: $0.25, $0.50, and $1. If the number of $0.25 coins is 8, and the number of $0.50 coins is 4, how many $1 coins does he have?
(1) The total value of the $1 coins in the piggy bank is 50% of the total value of all the coins.
(2) The $1 coins make up 25% of the total number of coins in the piggy bank.