Ans. value of x in both scenario = 1
Strategy 1:Area = 240 sq. meter
Electrical output per sq. meter = 0.5 kWH
Total electrical output = 240*0.5 = 120 kWH
Strategy 2: Area1 = 200 sq. meter
Electrical output per sq. meter for area1 = 0.4 kWH
Total electrical output for area1= 200*0.4 = 80 kWH
Area2 = 240 sq. meter
Electrical output per sq. meter for area2 = x kWH
Total electrical output for area2= 40*x = 40x kWH
Total electrical output= Electrical output for area1 + Electrical output for area2 = 80+40x
Now in Scenario 1(select for x), it is said that the electrical power in both strategies is same
So, 80+40x=120
=> 40x=40
=>x=1
In Scenario 2(select for y), it is mentioned that the energy in Area1 of strategy 2 is twice the energy in Area2 of strategy 2
So, 40x=80/2
=> x = 1
Therefore in both scenarios(value for x and y), the solution is 1
Bunuel
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A solar energy project involves installing solar panels over a total area of 240 square meters and has two design strategies to choose from. Strategy 1 uses the entire 240 square meters for a single high-efficiency solar panel setup, which provides an electrical output equal to 0.5kWH per square meter. Strategy 2 splits the area into two separate setups: 200 square meters with a slightly lower efficiency that provides an electrical output equal to 0.4kWH per square meter and the remaining 40 square meters with an output of x kWH per square meter. Both strategies are otherwise identical, and all electrical output is calculated at the end of the year.Select for
x the value of x at which the two strategies result in the same total electrical output, and select for
y the value at which the output from the 200 square meters setup would be exactly twice the additional output from the 40 square meters setup. Make only two selections, one in each column.