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31 May 2013, 22:31
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Difficulty:
45%
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Question Stats:
69% (01:54) correct
31%
(02:22)
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based on 639
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15 welders work at a constant rate they complete an order in 3 days. If after the first day, 9 welders start to work on the other project, how many more days the remaining welders will need to complete the rest of the order?
(A) 5
(B) 2
(C) 8
(D) 4
(E) 6
(A) 5
(B) 2
(C) 8
(D) 4
(E) 6
ConnectTheDots
GMAT 2: 770 Q50 V47
Posts: 239
31 May 2013, 22:54
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gmatquant25
15 welders work at a constant rate they complete an order in 3 days. If after the first day, 9 welders start to work on the other project, how many more days the remaining welders will need to complete the rest of the order?
(A)5
(B)2
(C)8
(D)4
(E)6
(A)5
(B)2
(C)8
(D)4
(E)6
LCM (15,3,9) = 45
Suppose Total work is 45 Units.
15 Welders = 45 Units / 3 days
15 Welders = 45/3 = 15 Units / day
1 Welder = 1 Unit/day
Day 1: everyone worked = 15 units, remaining 30 Units
After Day 1, I have 6 Welders (15 - 9), and I need to complete 30 Units.
1 Welder = 1 Unit/day
6 Welders = 6 Unit/day
for 30 Units, 30(total units)/ 6 (units per day) = 5 days
Answer A
31 May 2013, 23:25
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gmatquant25
15 welders work at a constant rate they complete an order in 3 days. If after the first day, 9 welders start to work on the other project, how many more days the remaining welders will need to complete the rest of the order?
(A)5
(B)2
(C)8
(D)4
(E)6
(A)5
(B)2
(C)8
(D)4
(E)6
\(15*r*3\) = 1 unit of work. Thus, rate of each worker =\(\frac{1}{45}\)
The amount of work done in 1 day with all 15 workers =\(\frac{1}{3}\). The amount of work left to be done by (15-9) workers = \(\frac{2}{3}\)
Let them take d days to complete this work-->\(6*r*d\) = 2/3--> \(6*\frac{1}{45}*d =\frac{2}{3}\)--> d= 5 days.
A.
