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30% of all fishermen in Piscataquis County are also hunters while only

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30% of all fishermen in Piscataquis County are also hunters while only  [#permalink]

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New post 17 Jul 2015, 00:31
3
12
00:00
A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

82% (02:09) correct 18% (02:33) wrong based on 255 sessions

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30% of all fishermen in Piscataquis County are also hunters while only 20% of all hunters are fishermen. If there are 1500 hunters in Piscataquis County then how many fishermen are there?

A. 800
B. 1000
C. 1200
D. 1500
E. 1800

Kudos for a correct solution.

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Re: 30% of all fishermen in Piscataquis County are also hunters while only  [#permalink]

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New post 17 Jul 2015, 00:54
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Let Hunter be h and fishermen be f

From given data

0.3f = 0.2h = 0.2 *1500

F = 1000
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Re: 30% of all fishermen in Piscataquis County are also hunters while only  [#permalink]

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New post 17 Jul 2015, 02:47
1
Bunuel wrote:
30% of all fishermen in Piscataquis County are also hunters while only 20% of all hunters are fishermen. If there are 1500 hunters in Piscataquis County then how many fishermen are there?

A. 800
B. 1000
C. 1200
D. 1500
E. 1800

Kudos for a correct solution.


Solved easily by a 2X2 matrix:

Text in black: given information
Text in red: calculated values

From the attached picture:

z= 1500

and 0.3y = 0.2z ---> 0.3y = 300 ---> y =1000, B is the correct answer.
Attachments

2X2 MATRIX.jpg
2X2 MATRIX.jpg [ 19.53 KiB | Viewed 2757 times ]

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Re: 30% of all fishermen in Piscataquis County are also hunters while only  [#permalink]

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New post 17 Jul 2015, 06:45
2
30%(fishermen) = 20%(hunters)

number of hunters = 1500.

so, 20%(1500) = 30%(fishermen)

number of fishermen = 300*100/30 = 1000. Ans (B).
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Re: 30% of all fishermen in Piscataquis County are also hunters while only  [#permalink]

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New post 17 Jul 2015, 06:50
2
Bunuel wrote:
30% of all fishermen in Piscataquis County are also hunters while only 20% of all hunters are fishermen. If there are 1500 hunters in Piscataquis County then how many fishermen are there?

A. 800
B. 1000
C. 1200
D. 1500
E. 1800

Kudos for a correct solution.



If we draw the Venn Diagram, we can see that

30% of Fisherman = 20% of Hunters (Common Space)

We know, Total Hunters = 1500, Hence 20% H = 300.

This is equal to 30% of Fisherman. => 30%F = 300 => F= 1000

Option B.

Direct way: Solve 0.3 F = 0.2 H => F = (2/3) * 1500 => F = 1000
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Re: 30% of all fishermen in Piscataquis County are also hunters while only  [#permalink]

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New post 17 Jul 2015, 07:24
1
Bunuel wrote:
30% of all fishermen in Piscataquis County are also hunters while only 20% of all hunters are fishermen. If there are 1500 hunters in Piscataquis County then how many fishermen are there?

A. 800
B. 1000
C. 1200
D. 1500
E. 1800

Kudos for a correct solution.


Let total no. of Fishermen =100
Therefore, Fishermen who are also hunters=30
And, Hunters who are fisherman=30*5=150( Since, only 20% of all hunters are fishermen)
Therefore, if there are 1500 hunters, there will be 300 hunters who are fishermen and 700 Fishermen who are not hunters
Answer =700+300=1000
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Re: 30% of all fishermen in Piscataquis County are also hunters while only  [#permalink]

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New post 19 Jul 2015, 11:51
Bunuel wrote:
30% of all fishermen in Piscataquis County are also hunters while only 20% of all hunters are fishermen. If there are 1500 hunters in Piscataquis County then how many fishermen are there?

A. 800
B. 1000
C. 1200
D. 1500
E. 1800

Kudos for a correct solution.


800score Official Solution:

People who do both hunting and fishing make 30% of fishermen and 20% of hunters. There are 1500 hunters so 1500 × 20% = 300 pers. do both hunting and fishing. Same people make 30% of all fishermen.30% of fishermen = 300 pers.

Fishermen = (300 / 30) × 100 pers. = 1000 pers.

The correct answer is choice (B).
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Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

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Re: 30% of all fishermen in Piscataquis County are also hunters while only  [#permalink]

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New post 13 Mar 2017, 00:00
Let total fishermen is x
total hunters is y
as per the question stem
(30/100)*x=(20/100)*y
also y=1500
calculating x we get x=1000
answer B
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Re: 30% of all fishermen in Piscataquis County are also hunters while only  [#permalink]

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New post 15 Mar 2017, 15:48
1
Bunuel wrote:
30% of all fishermen in Piscataquis County are also hunters while only 20% of all hunters are fishermen. If there are 1500 hunters in Piscataquis County then how many fishermen are there?

A. 800
B. 1000
C. 1200
D. 1500
E. 1800


Since 20% of all hunters in Piscataquis County are also fishermen, there are 0.2 x 1500 = 300 hunters who are also fishermen. Since 30% of all fishermen in Piscataquis County are also hunters, we can let f = the total number of fisherman in the county and create the following equation to solve for f:

300 = 0.3f

3000 = 3f

f = 1000

Answer: B
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Re: 30% of all fishermen in Piscataquis County are also hunters while only  [#permalink]

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New post 01 Jul 2017, 20:50
i think this question is a copy of official DS question in overlapping set . Where the question is a C trap type :-) :-)
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Re: 30% of all fishermen in Piscataquis County are also hunters while only  [#permalink]

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New post 06 Aug 2018, 08:02
Fisherman = F
Hunters = H

Asks for:
Q: F=?

Gives:
0.3F=0.2H
H=1500

Solution:
0.3F=0.2(1500)
0.3F=300
F=300/0.3
F=1000

Ans. (B)
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Re: 30% of all fishermen in Piscataquis County are also hunters while only &nbs [#permalink] 06 Aug 2018, 08:02
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