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A=0.abc, where a, b and c are distinct digits, is A>34?  [#permalink]

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Difficulty:   85% (hard)

Question Stats: 48% (02:25) correct 52% (02:39) wrong based on 61 sessions

HideShow timer Statistics A=0.abc, where a, b and c are distinct digits, is $$A>\frac{3}{4}$$?

(1) a/b=2 and b/c=3/4
(2) 2(a+b)>10a+b

Originally posted by kiran1213 on 24 Dec 2018, 11:09.
Last edited by chetan2u on 07 May 2019, 23:25, edited 1 time in total.
edited the question
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A=0.abc, where a, b and c are distinct digits, is A>34?  [#permalink]

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Statement 1:
if $$a:b = 2:1$$ & $$b:c = 3:4$$, then $$a:b:c = 6:3:4$$
since a,b&c are single-digit numbers, the only valid value for $$A = 0.634$$ , which is $$<\frac{3}{4}$$ --> sufficient

Statement 2:
if $$2(a+b)>10a+b$$, then it can be simplified to $$b>8a$$.
so if $$a=1$$, then $$b>8$$ (9,10,...) and if $$a=2$$, then $$b>9$$ (10,11,...)
since a&b are single-digit numbers, the only valid value for $$b = 9$$ and $$a = 1$$
so $$A = 0.19c$$, which is $$<\frac{3}{4}$$ regardless of the value of $$c$$ --> sufficient

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Originally posted by Mahmoudfawzy83 on 24 Dec 2018, 14:07.
Last edited by Mahmoudfawzy83 on 13 May 2019, 01:15, edited 2 times in total.
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Re: A=0.abc, where a, b and c are distinct digits, is A>34?  [#permalink]

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I think the question is , "is A>3/4?". A cannot be greater than 2.
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Re: A=0.abc, where a, b and c are distinct digits, is A>34?  [#permalink]

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poor quality question.
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Re: A=0.abc, where a, b and c are distinct digits, is A>34?  [#permalink]

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A=0.abc, where a, b and c are distinct digits, is $$A>\frac{3}{4}$$?
So, A>0.75, which means is a$$\geq{7}$$

(1) a/b=2 and b/c=3/4...
a=2b, and 4b=3c...
4b=3c tells us that c can be 4 or 8..
a) if c is 4
4b=3*c=3*4...b=3, and a=2b=2*3=6
A=0.634...Ans NO
b) if c is 8
4b=3*c=3*8...b=6, and a=2b=2*6=12.. BUT a is a digit, so cannot be >9.

So, only possibility is A=0.634...Ans NO
Suff

(2) 2(a+b)>10a+b
2a+2b>10a+b....b>8a....
Since b is <10, only possibility for a is 1..
Hence ans NO
suff

D

NOTE.. You have different values of a and b from statement I and II. Will not be the case in actuals.
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Re: A=0.abc, where a, b and c are distinct digits, is A>34?  [#permalink]

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kiran1213 wrote:
A=0.abc, where a, b and c are distinct digits, is $$A>\frac{3}{4}$$?

(1) a/b=2 and b/c=3/4
(2) 2(a+b)>10a+b

Can somebody help me understand the question? A=0.abc I read this as A is equal to 0 multiplied by a*b*c.
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Re: A=0.abc, where a, b and c are distinct digits, is A>34?  [#permalink]

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saikeish15 wrote:
kiran1213 wrote:
A=0.abc, where a, b and c are distinct digits, is $$A>\frac{3}{4}$$?

(1) a/b=2 and b/c=3/4
(2) 2(a+b)>10a+b

Can somebody help me understand the question? A=0.abc I read this as A is equal to 0 multiplied by a*b*c.

Firstly, the question will mention the same way you have written (A*B*C) if the intention is to multiply the digits or it will be mentioned explicitly in the question stem itself ( eg multiplication of three numbers).
Secondly, do you think that there would any point to ask such question because any number multiplied by 0 will always yield you zero, then how can it be greater than 0; So you could have answered this question even without the 2 statements given.
Give a thought!
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Re: A=0.abc, where a, b and c are distinct digits, is A>34?  [#permalink]

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BarcaForLife wrote:
saikeish15 wrote:
kiran1213 wrote:
A=0.abc, where a, b and c are distinct digits, is $$A>\frac{3}{4}$$?

(1) a/b=2 and b/c=3/4
(2) 2(a+b)>10a+b

Can somebody help me understand the question? A=0.abc I read this as A is equal to 0 multiplied by a*b*c.

Firstly, the question will mention the same way you have written (A*B*C) if the intention is to multiply the digits or it will be mentioned explicitly in the question stem itself ( eg multiplication of three numbers).
Secondly, do you think that there would any point to ask such question because any number multiplied by 0 will always yield you zero, then how can it be greater than 0; So you could have answered this question even without the 2 statements given.
Give a thought!

Ah. Sorry. I had a brain fade. Re-read the question again today and realized the absurdity of my doubt! Re: A=0.abc, where a, b and c are distinct digits, is A>34?   [#permalink] 12 May 2019, 21:57
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