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Bunuel
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Bunuel
A bug is traveling between 2 points so that the distance it travels every day is half of the distance it traveled the day before. If the distance between the two points is 14 units, how much should it travel on the first day in order to reach its destination in 3 days?

A. 4
B. 14/3
C. 6
D. 7
E. 8


Distance between two points is 14 units.

Say distance traveled on first, second,and third day =\(d\), \(\frac{d}{2}\), \(\frac{d}{4}\) respectively as given in question.

\(d\)\(+\) \(\frac{d}{2}\) \(+\) \(\frac{d}{4}\) \(= 14\)

d = 8

Hence, distance traveled on day first = 8 units (E)
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Bunuel
A bug is traveling between 2 points so that the distance it travels every day is half of the distance it traveled the day before. If the distance between the two points is 14 units, how much should it travel on the first day in order to reach its destination in 3 days?

A. 4
B. 14/3
C. 6
D. 7
E. 8

We can also back-solve the question using options.
8+8/2+8/4 = 8+4+2 = 12
Ans :E
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Bunuel
A bug is traveling between 2 points so that the distance it travels every day is half of the distance it traveled the day before. If the distance between the two points is 14 units, how much should it travel on the first day in order to reach its destination in 3 days?

A. 4
B. 14/3
C. 6
D. 7
E. 8

We can let x = the distance the bug travels on the first day.

Day 1 = x

Day 2 = (1/2)x

Day 3 = (1/4)x

We can create the following equation:

(x + (1/2)x + (1/4)x) = 14

Multiplying the entire equation by 4, we have:

4x + 2x + x = 56

7x = 56

x = 8

Answer: E
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