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A carpenter constructed a rectangular sandbox with a [#permalink]
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 13 Aug 2012, 07:02
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Re: A carpenter constructed a rectangular sandbox with a [#permalink]
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13 Aug 2012, 07:02
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Re: A carpenter constructed a rectangular sandbox with a [#permalink]
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13 Aug 2012, 08:16
Let x,y & z be L,W & H so xyz = 10 cu ft As per question if we double the lengths on all dimensions we get (2x)(2y)(2z)=8 xyz= 8*10= 80 Answer: D
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Re: A carpenter constructed a rectangular sandbox with a [#permalink]
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13 Aug 2012, 08:21
volume =l*b*h =10 cubic feet
Now we have twice as long, twice as wide, and twice as high as the first sandbox,
L=2*l
B=2*b
H=2*h
final volume =L*B*H =2*l*2*b*2*h=8*(l*b*h) =8*10=80 cubic feet
answer is D
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Re: A carpenter constructed a rectangular sandbox with a [#permalink]
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13 Aug 2012, 09:16
V=LWH
Original Volume = 10
In order to keep things simple. I made Height = 5, Length = 2, and Width = 1
The second statement says double everything.
Height = 10, Length = 4, and Width = 2
V = 80
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Re: A carpenter constructed a rectangular sandbox with a [#permalink]
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17 Aug 2012, 01:02
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Re: A carpenter constructed a rectangular sandbox with a [#permalink]
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12 Apr 2013, 09:52
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A quick note on doubling. When you double a length you have 2*L1. When you double all lengths of a rectangle you have (2*L1)(2*L2) = A. An increase of 2^2 or 4. When you double all lengths of a rectangular prism you have (2*L1)(2*L2)(2*L3) = V. An increase of 2^3 or 8.
This leads to the basic relationship:
Line: 2*original size
Rectangle: 4*original size
Rectangular Prism: 8*original size
You can do the math out or memorize this relationship to speed things up.
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Re: A carpenter constructed a rectangular sandbox with a [#permalink]
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01 Dec 2014, 16:17
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Re: A carpenter constructed a rectangular sandbox with a [#permalink]
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02 Dec 2014, 02:30
Answer = (D) 80 Original volume = 10 cubic feet All 3 dimensions made "twice" New volume = 10 * 2 * 2 * 2 = 80
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Re: A carpenter constructed a rectangular sandbox with a [#permalink]
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24 May 2016, 10:43
Bunuel wrote: A carpenter constructed a rectangular sandbox with a capacity of 10 cubic feet. If the carpenter were to make a similar sandbox twice as long, twice as wide, and twice as high as the first sandbox, what would be the capacity, in cubic feet, of the second sandbox?
(A) 20
(B) 40
(C) 60
(D) 80
(E) 100 We are given a rectangular sandbox with a given capacity, which is the volume of the sandbox. Therefore, we know that the volume of the sandbox is: (L)(W)(H) = 10 cubic feet We then are told that the carpenter doubles the length, the width, and the height. We can represent this doubling as (2L)(2W)(2H). Thus (2L)(2W)(2H) = (2)(2)(2)(L)(W)(H) = (2)(2)(2)(10) = 80 cubic feet Answer D.
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Re: A carpenter constructed a rectangular sandbox with a [#permalink]
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31 May 2017, 02:22
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Re: A carpenter constructed a rectangular sandbox with a
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