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A certain bakery has 6 employees. It pays annual salaries of

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A certain bakery has 6 employees. It pays annual salaries of  [#permalink]

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Updated on: 05 Mar 2013, 04:38
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I came across the following GMATPrep® question:

A certain bakery has 6 employees. It pays annual salaries of $14,000 to each of 2 employees,$16,000 to 1 employee, and $17,000 to each of the remaining 3 employees. The average (arithmetic mean) annual salary of these employees is closest to which of the following? (A)$15,200
(B) $15,500 (C)$15,800
(D) $16,000 (E)$16,400

Lets try to solve this problem using some unconventional method, to save time.
First and foremost, lets not consider the three zeros, we'll add them afterwards

The generic method to solve this question would be adding the salaries and dividing by 6 - (14 x 2 + 16 + 17 x 3) x1000/6 This would give the right answer.

The other way, to solve this average problem, using lesser calculations is:

Since the salaries are 14, 16, 17, it would mean that the average is going to be more than 14. We have, 14 x 2 and 17 x 3.

Had it been, 14 x 3 and 17 x 3, we could have concluded, the average would be (14 + 17) / 2 = 15.5

But we have 14 x 2 and 16 x 1, which would mean, the average should increase by a small amount. This would eliminate most of the choices - A B E

We are left with 15800 and 16000.

An increase of 2 in the salary, will increase the average by 2 / 6 = .36

Thus you'll get the answer 15.86

We can avoid the last step calculation too, if we observe that the increase is from 14 to 16, and will that result in an increase of .5 ?

If you have some other good and faster method to solve this problem, please share.

_________________

Give KUDOS if the post helps you...

Originally posted by UmangMathur on 05 Mar 2013, 04:31.
Last edited by Bunuel on 05 Mar 2013, 04:38, edited 1 time in total.
Renamed the topic, edited the question and the tags.
Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 8188
Location: Pune, India
Re: A certain bakery has 6 employees. It pays annual salaries of  [#permalink]

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10 Mar 2013, 23:53
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3
LalaB wrote:
İ am not sure that my method is ideal. So, I will be happy to hear experts' opinion on this -

we have a set 14 14 16 17 17 17
lets derive from it two sets -
1) 12 12 18 18 18 18 2) +2 +2 -2 -3 (+2 means we need +2 to get 14 from 12; -2 means we need -2 to get 16 from 18 etc)

12*2/6 +18*4/6 =4+12=16 ; 16 is the mean of the 1st set

-1/6 is the mean of the 2nd set

16-0.1666= 15.8333

ans is C

I see what you are doing and it is fine but the logic behind the approach is not very clear to me. (By the way, good call on dropping the '000s. They add no value and just make the solution cumbersome)

If I were to split it into two sets, they would be:
16, 16, 16, 16, 16, 16 - so that I know that the mean here is certainly none other than 16. 16 is the middle number and the means is expected to be something around it.
-2, -2, 0, +1, +1, +1 - because actually the first term is 14 i.e. 2 less and so on.
This adds up to -1 giving an average of -1/6

So average = 16 - 1/6 = 15.8333

(Essentially the same thing)
_________________

Karishma
Veritas Prep GMAT Instructor

Save up to $1,000 on GMAT prep through 8/20! Learn more here > GMAT self-study has never been more personalized or more fun. Try ORION Free! General Discussion Verbal Forum Moderator Joined: 10 Oct 2012 Posts: 615 Re: A certain bakery has 6 employees. It pays annual salaries of [#permalink] Show Tags 05 Mar 2013, 05:16 1 1 UmangMathur wrote: I came across the following GMATPrep® question: A certain bakery has 6 employees. It pays annual salaries of$14,000 to each of 2 employees, $16,000 to 1 employee, and$17,000 to each of the remaining 3 employees. The average (arithmetic mean) annual salary of these employees is closest to which of the following?

(A) $15,200 (B)$15,500
(C) $15,800 (D)$16,000
(E) $16,400 Let the salary for each person be 14. Thus, the bakery ends up getting 2 + 3*3 = 11 as extra. This again has to be divided among 6 people. 12/6 = 2 which makes it 14+2 =16. Thus, as it is 11/6, it will be somewhere close to 16 and less than that. Also, 1/6 = 0.166. Thus 10/6 = 1.66 which gives the final salary after redistribution as 15.66. Thus, the answer is C. _________________ Senior Manager Joined: 23 Oct 2010 Posts: 361 Location: Azerbaijan Concentration: Finance Schools: HEC '15 (A) GMAT 1: 690 Q47 V38 Re: A certain bakery has 6 employees. It pays annual salaries of [#permalink] Show Tags 10 Mar 2013, 03:52 İ am not sure that my method is ideal. So, I will be happy to hear experts' opinion on this - we have a set 14 14 16 17 17 17 lets derive from it two sets - 1) 12 12 18 18 18 18 2) +2 +2 -2 -3 (+2 means we need +2 to get 14 from 12; -2 means we need -2 to get 16 from 18 etc) 12*2/6 +18*4/6 =4+12=16 ; 16 is the mean of the 1st set -1/6 is the mean of the 2nd set 16-0.1666= 15.8333 ans is C _________________ Happy are those who dream dreams and are ready to pay the price to make them come true I am still on all gmat forums. msg me if you want to ask me smth Manager Status: Breaking my head!! Joined: 27 Jan 2013 Posts: 66 Location: India Concentration: General Management, Operations GMAT 1: 740 Q50 V40 GPA: 3.51 WE: Other (Transportation) Re: A certain bakery has 6 employees. It pays annual salaries of [#permalink] Show Tags 11 Mar 2013, 00:42 1 Thoughtosphere wrote: I came across the following GMATPrep® question: A certain bakery has 6 employees. It pays annual salaries of$14,000 to each of 2 employees, $16,000 to 1 employee, and$17,000 to each of the remaining 3 employees. The average (arithmetic mean) annual salary of these employees is closest to which of the following?

(A) $15,200 (B)$15,500
(C) $15,800 (D)$16,000
(E) $16,400 Lets try to solve this problem using some unconventional method, to save time. First and foremost, lets not consider the three zeros, we'll add them afterwards The generic method to solve this question would be adding the salaries and dividing by 6 - (14 x 2 + 16 + 17 x 3) x1000/6 This would give the right answer. The other way, to solve this average problem, using lesser calculations is: Since the salaries are 14, 16, 17, it would mean that the average is going to be more than 14. We have, 14 x 2 and 17 x 3. Had it been, 14 x 3 and 17 x 3, we could have concluded, the average would be (14 + 17) / 2 = 15.5 But we have 14 x 2 and 16 x 1, which would mean, the average should increase by a small amount. This would eliminate most of the choices - A B E We are left with 15800 and 16000. An increase of 2 in the salary, will increase the average by 2 / 6 = .36 Thus you'll get the answer 15.86 We can avoid the last step calculation too, if we observe that the increase is from 14 to 16, and will that result in an increase of .5 ? If you have some other good and faster method to solve this problem, please share. I am wondering why we cannot just take the average of the numbers the conventional way instead of looking at novel ways to solve this simple problem We can ignore the zeroes and just go ahead and compute (14*2 + 16 + 17*3) / 6....which approximately comes to a little less than 16 and we have our answer. Took me less than 30 secs Veritas Prep GMAT Instructor Joined: 16 Oct 2010 Posts: 8188 Location: Pune, India Re: A certain bakery has 6 employees. It pays annual salaries of [#permalink] Show Tags 11 Mar 2013, 01:26 Dipankar6435 wrote: I am wondering why we cannot just take the average of the numbers the conventional way instead of looking at novel ways to solve this simple problem We can ignore the zeroes and just go ahead and compute (14*2 + 16 + 17*3) / 6....which approximately comes to a little less than 16 and we have our answer. Took me less than 30 secs We most certainly can and it is quite easy to do in this question. Nevertheless, people like to keep a repertoire of various methods that can be used to solve questions of a particular type. Depending on the values given in the question, innovative methods can be much faster than conventional approaches. _________________ Karishma Veritas Prep GMAT Instructor Save up to$1,000 on GMAT prep through 8/20! Learn more here >

GMAT self-study has never been more personalized or more fun. Try ORION Free!

Senior Manager
Joined: 23 Oct 2010
Posts: 361
Location: Azerbaijan
Concentration: Finance
Schools: HEC '15 (A)
GMAT 1: 690 Q47 V38
A certain bakery has 6 employees. It pays annual salaries of  [#permalink]

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11 Mar 2013, 09:05
Dipankar6435 wrote:

I am wondering why we cannot just take the average of the numbers the conventional way instead of looking at novel ways to solve this simple problem :
We can ignore the zeroes and just go ahead and compute (14*2 + 16 + 17*3) / 6....which approximately comes to a little less than 16 and we have our answer. Took me less than 30 secs :wink:

Read the article -"Want a 750+? Do this question in 30 seconds", and u will get the answer

https://www.manhattangmat.com/blog/index.php/2013/03/04/want-a-750-do-this-question-in-30-seconds/

to VeritasPrepKarishma
Thanks for checking my approach and giving good advice!
_________________

Happy are those who dream dreams and are ready to pay the price to make them come true

I am still on all gmat forums. msg me if you want to ask me smth

Intern
Joined: 19 Jan 2014
Posts: 26
Re: A certain bakery has 6 employees. It pays annual salaries of  [#permalink]

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25 Jan 2014, 21:27
VeritasPrepKarishma wrote:
LalaB wrote:
İ am not sure that my method is ideal. So, I will be happy to hear experts' opinion on this -

we have a set 14 14 16 17 17 17
lets derive from it two sets -
1) 12 12 18 18 18 18 2) +2 +2 -2 -3 (+2 means we need +2 to get 14 from 12; -2 means we need -2 to get 16 from 18 etc)

12*2/6 +18*4/6 =4+12=16 ; 16 is the mean of the 1st set

-1/6 is the mean of the 2nd set

16-0.1666= 15.8333

ans is C

I see what you are doing and it is fine but the logic behind the approach is not very clear to me. (By the way, good call on dropping the '000s. They add no value and just make the solution cumbersome)

If I were to split it into two sets, they would be:
16, 16, 16, 16, 16, 16 - so that I know that the mean here is certainly none other than 16. 16 is the middle number and the means is expected to be something around it.
-2, -2, 0, +1, +1, +1 - because actually the first term is 14 i.e. 2 less and so on.
This adds up to -1 giving an average of -1/6

So average = 16 - 1/6 = 15.8333

(Essentially the same thing)

I like this method but I have 2 questions.
1. When is it more time saving to use it? As numbers in these problems allow us to solve this problem very fast with the traditional method.
2. 16 - 1/6= 15.83 it takes me more time to calculate this than 95/6... Is there any faster way to calculate 16-1/6 other then (6*16+1)/6?

Thank you so much.
Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 8188
Location: Pune, India
Re: A certain bakery has 6 employees. It pays annual salaries of  [#permalink]

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27 Jan 2014, 03:04
bytatia wrote:

I like this method but I have 2 questions.
1. When is it more time saving to use it? As numbers in these problems allow us to solve this problem very fast with the traditional method.
2. 16 - 1/6= 15.83 it takes me more time to calculate this than 95/6... Is there any faster way to calculate 16-1/6 other then (6*16+1)/6?

Thank you so much.

How about: 147, 156, 160, 143, 180, 167
You might appreciate the deviations method more here. Also, check out this link for more on this method: http://www.veritasprep.com/blog/2012/05 ... eviations/

You should know that 1/6 = .166666... or approximately .17
You must memorize some important fraction-percentage equivalents. Check here: http://www.veritasprep.com/blog/2011/02 ... rcentages/
1/6 is 16.7% which is .167 in decimal form.
_________________

Karishma
Veritas Prep GMAT Instructor

Save up to $1,000 on GMAT prep through 8/20! Learn more here > GMAT self-study has never been more personalized or more fun. Try ORION Free! SVP Status: The Best Or Nothing Joined: 27 Dec 2012 Posts: 1835 Location: India Concentration: General Management, Technology WE: Information Technology (Computer Software) Re: A certain bakery has 6 employees. It pays annual salaries of [#permalink] Show Tags 09 Sep 2014, 00:17 1 Thoughtosphere wrote: I came across the following GMATPrep® question: A certain bakery has 6 employees. It pays annual salaries of$14,000 to each of 2 employees, $16,000 to 1 employee, and$17,000 to each of the remaining 3 employees. The average (arithmetic mean) annual salary of these employees is closest to which of the following?

(A) $15,200 (B)$15,500
(C) $15,800 (D)$16,000
(E) $16,400 Lets try to solve this problem using some unconventional method, to save time. First and foremost, lets not consider the three zeros, we'll add them afterwards The generic method to solve this question would be adding the salaries and dividing by 6 - (14 x 2 + 16 + 17 x 3) x1000/6 This would give the right answer. The other way, to solve this average problem, using lesser calculations is: Since the salaries are 14, 16, 17, it would mean that the average is going to be more than 14. We have, 14 x 2 and 17 x 3. Had it been, 14 x 3 and 17 x 3, we could have concluded, the average would be (14 + 17) / 2 = 15.5 But we have 14 x 2 and 16 x 1, which would mean, the average should increase by a small amount. This would eliminate most of the choices - A B E We are left with 15800 and 16000. An increase of 2 in the salary, will increase the average by 2 / 6 = .36 Thus you'll get the answer 15.86 We can avoid the last step calculation too, if we observe that the increase is from 14 to 16, and will that result in an increase of .5 ? If you have some other good and faster method to solve this problem, please share. Dropping the zero's $$\frac{14*2 + 16*1 + 17*3}{6} = \frac{95}{6}$$ $$\frac{96}{6} = 16$$; so $$\frac{95}{6}$$ would be just below 16 15800 fits in best Answer = C (Solved in 15 seconds) _________________ Kindly press "+1 Kudos" to appreciate Intern Joined: 05 Aug 2015 Posts: 46 Re: A certain bakery has 6 employees. It pays annual salaries of [#permalink] Show Tags 10 Apr 2016, 12:59 Someone posted the solution below to the question -- I understood the approach up until the last part of adding 10. Why does adding 10 works / what's the conceptual reason? Thank you! SOLUTION: As we are very good at Tables up to 10×10… 4*2=8 6*1=6 7*3=21 Total…35 Divide by 6=5.8333 Add 10…15.8333 …That’s all… _________________ Working towards 25 Kudos for the Gmatclub Exams - help meee I'm poooor Intern Joined: 05 Jun 2016 Posts: 25 Re: A certain bakery has 6 employees. It pays annual salaries of [#permalink] Show Tags 24 Nov 2016, 05:58 I mistook this problem to be a weighted average problem. As a result, I chose (E) 16,400 since there are 3 people getting paid 17,000$. Can someone please point out the error in this reasoning?
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Joined: 05 Jun 2016
Posts: 25
Re: A certain bakery has 6 employees. It pays annual salaries of  [#permalink]

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24 Nov 2016, 05:59
VeritasPrepKarishma wrote:
LalaB wrote:
İ am not sure that my method is ideal. So, I will be happy to hear experts' opinion on this -

we have a set 14 14 16 17 17 17
lets derive from it two sets -
1) 12 12 18 18 18 18 2) +2 +2 -2 -3 (+2 means we need +2 to get 14 from 12; -2 means we need -2 to get 16 from 18 etc)

12*2/6 +18*4/6 =4+12=16 ; 16 is the mean of the 1st set

-1/6 is the mean of the 2nd set

16-0.1666= 15.8333

ans is C

I see what you are doing and it is fine but the logic behind the approach is not very clear to me. (By the way, good call on dropping the '000s. They add no value and just make the solution cumbersome)

If I were to split it into two sets, they would be:
16, 16, 16, 16, 16, 16 - so that I know that the mean here is certainly none other than 16. 16 is the middle number and the means is expected to be something around it.
-2, -2, 0, +1, +1, +1 - because actually the first term is 14 i.e. 2 less and so on.
This adds up to -1 giving an average of -1/6

So average = 16 - 1/6 = 15.8333

(Essentially the same thing)

Hello,

I mistook this problem to be a weighted average problem. As a result, I chose (E) 16,400 since there are 3 people getting paid 17,000$. Can someone please point out the error in this reasoning? Veritas Prep GMAT Instructor Joined: 16 Oct 2010 Posts: 8188 Location: Pune, India Re: A certain bakery has 6 employees. It pays annual salaries of [#permalink] Show Tags 24 Nov 2016, 22:53 gatreya14 wrote: VeritasPrepKarishma wrote: LalaB wrote: İ am not sure that my method is ideal. So, I will be happy to hear experts' opinion on this - we have a set 14 14 16 17 17 17 lets derive from it two sets - 1) 12 12 18 18 18 18 2) +2 +2 -2 -3 (+2 means we need +2 to get 14 from 12; -2 means we need -2 to get 16 from 18 etc) 12*2/6 +18*4/6 =4+12=16 ; 16 is the mean of the 1st set -1/6 is the mean of the 2nd set 16-0.1666= 15.8333 ans is C I see what you are doing and it is fine but the logic behind the approach is not very clear to me. (By the way, good call on dropping the '000s. They add no value and just make the solution cumbersome) If I were to split it into two sets, they would be: 16, 16, 16, 16, 16, 16 - so that I know that the mean here is certainly none other than 16. 16 is the middle number and the means is expected to be something around it. -2, -2, 0, +1, +1, +1 - because actually the first term is 14 i.e. 2 less and so on. This adds up to -1 giving an average of -1/6 So average = 16 - 1/6 = 15.8333 (Essentially the same thing) Hello, I mistook this problem to be a weighted average problem. As a result, I chose (E) 16,400 since there are 3 people getting paid 17,000$. Can someone please point out the error in this reasoning?

It is a weighted average problem.
C1 = 14k, w1 = 2
C2 = 16K, w2 = 1
C3 = 17K, w3 = 3

Cavg = (C1*w1 + C2*w2 + C3*w3)/(w1 + w2 + w3)
Cavg = (2*14 + 1*16 + 3*17)/(2 + 1 + 3)
Cavg = 15.833
_________________

Karishma
Veritas Prep GMAT Instructor

Save up to $1,000 on GMAT prep through 8/20! Learn more here > GMAT self-study has never been more personalized or more fun. Try ORION Free! Target Test Prep Representative Status: Head GMAT Instructor Affiliations: Target Test Prep Joined: 04 Mar 2011 Posts: 2727 Re: A certain bakery has 6 employees. It pays annual salaries of [#permalink] Show Tags 29 Jan 2018, 11:03 UmangMathur wrote: I came across the following GMATPrep® question: A certain bakery has 6 employees. It pays annual salaries of$14,000 to each of 2 employees, $16,000 to 1 employee, and$17,000 to each of the remaining 3 employees. The average (arithmetic mean) annual salary of these employees is closest to which of the following?

(A) $15,200 (B)$15,500
(C) $15,800 (D)$16,000
(E) $16,400 We can set up the weighted average equation: [2(14,000) + 16,000 + 3(17,000)]/6 (28,0000 + 16,000 + 51,000)/6 = 95,000/6 ≈15,800 Answer: C _________________ Jeffery Miller Head of GMAT Instruction GMAT Quant Self-Study Course 500+ lessons 3000+ practice problems 800+ HD solutions Manager Joined: 03 Oct 2016 Posts: 135 Re: A certain bakery has 6 employees. It pays annual salaries of [#permalink] Show Tags 31 May 2018, 07:22 VeritasPrepKarishma wrote: Hello, I mistook this problem to be a weighted average problem. As a result, I chose (E) 16,400 since there are 3 people getting paid 17,000$. Can someone please point out the error in this reasoning?

It is a weighted average problem.
C1 = 14k, w1 = 2
C2 = 16K, w2 = 1
C3 = 17K, w3 = 3

Cavg = (C1*w1 + C2*w2 + C3*w3)/(w1 + w2 + w3)
Cavg = (2*14 + 1*16 + 3*17)/(2 + 1 + 3)
Cavg = 15.833

VeritasPrepKarishma if we go by weighted average then the answer should be closer to 17, right? 17k has 3 pointers in comparison to other two weights so the answer should incline towards higher value. Pls explain.
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Re: A certain bakery has 6 employees. It pays annual salaries of &nbs [#permalink] 31 May 2018, 07:22
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