AmoyV
# of half hours = 4
Rings for half hours = 4*2=8....(1)
# of full hours = 4
Rings for full hours = 4*4=16...(2)
Additional rings = 7+8+9+10=34...(3)
(1)+(2)+(3)=8+16+34=58
P.s. Where did I go wrong here?
Hi,
I believe you did not go wrong but the there is something in the wording of the question itself, albeit its good idea.
I agree with you on step 1 & 2. However, I understood the wording in the question as follows:
(four times at the hour plus an additional number of rings) require equal to what ever time it. My interpretation will be:
@ 7 o'clock, it will ring 4 (calculated in step 2) + 3 rings = 7 rings (to be equal the time what ever it is)
@ 8 o'clock, it will ring 4 (calculated in step 2) + 4 rings = 8 rings (to be equal the time what ever it is)
@ 9 o'clock, it will ring 4 (calculated in step 2) + 5 rings = 9 rings (to be equal the time what ever it is)
10 o'clock, it will ring 4 (calculated in step 2) + 6 rings = 10 rings (to be equal the time what ever it is)
Hence step 3:
3+4+5+6=18
Step 1, 2 & 3
8+16+18= 42
Answer: C. This is what I got according my understanding.
In some free resources, they do not consume time in high quality wording. Here is the source
https://www.hub4tech.com/certain-church- ... ll-twice-h