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555-605 Level|   Word Problems|                        
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Bunuel
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D

51752*181*113 or
51000*180*113 or
50000*200*100
=10^9

hope it helps
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Bunuel
A certain manufacturer sells its products to stores in 113 different regions worldwide, with an average (arithmetic mean) of 181 stores per region. If last year these stores sold an average of 51,752 units of the manufacturer’s product per store, which of the following is closest to the total number of units of manufacturer’s product sold worldwide last year?

A) 10^6
B) 10^7
C) 10^8
D) 10^9
E) 10^10

Use approximation ab initio

113 ~ 100
181 ~ 200
51,752 ~ 50000

So, 113 *181 *51,752 ~ 100*200*50000 =>20000*50000 = 1000000000 =10^9

Hence answer will be (D) 10^9
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Bunuel
A certain manufacturer sells its products to stores in 113 different regions worldwide, with an average (arithmetic mean) of 181 stores per region. If last year these stores sold an average of 51,752 units of the manufacturer’s product per store, which of the following is closest to the total number of units of manufacturer’s product sold worldwide last year?

A) 10^6
B) 10^7
C) 10^8
D) 10^9
E) 10^10

We are given that a certain manufacturer sells its products to stores in 113 different regions, with an average (arithmetic mean) of 181 stores per region and 51,752 units per store.

Since we are asked, which of the following is closest to the total number of units of manufacturer’s product sold worldwide last year, we can use estimation.

113 ≈ 100

181 ≈ 200

51,752 ≈ 50,000

Thus, the approximate number of units sold worldwide last year was:
100 x 200 x 50,000 = 1,000,000,000 = 10^9

Answer: D
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Excellent Question.

Testing out Knowledge on approximation.

Total Sold goods => 181*113*51752 => 200*100*52000 (Approx.) -> 1040000000 => 104 Crores => 100 Crores Approx => 10^9

Hence D
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1. 181 Stores x 113 regions = 20,453
2. 20,453 x 51,752 (I worked this out the long way but scientific notation is faster)
3. 2 x 10^4 x 5 x 10^4 = 10 x 10^8 (just add exponents since base and exponent is the same)
4. 10^9

Answer (D)
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As from question statement:
181*131*51,752
For approximation
180*(100+13)*50,000
180*(100+10)*50,000
(18000+1800)*50,000
~20,000*50,000
10^9
Key is to approximate at each step to make calculations more easier.

Answer D

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how do we know what is the correct level of approximation ?

I tried

180 * 110 * 52000 = which gives a 10^8
why cant this be the answer ?
Bunuel can you please tell me how much of an approximation is correct on the gmat ?
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113 ~ 100
181 ~ 200
51,752 ~ 50000

so 10^2 X (2*10^2) X (5*10^4)

Here 2 and 5 adds 1 to 10 power

add 1 + 2 + 2 + 4 = 10^9
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Bunuel
A certain manufacturer sells its products to stores in 113 different regions worldwide, with an average (arithmetic mean) of 181 stores per region. If last year these stores sold an average of 51,752 units of the manufacturer’s product per store, which of the following is closest to the total number of units of manufacturer’s product sold worldwide last year?

A) 10^6
B) 10^7
C) 10^8
D) 10^9
E) 10^10


\(113*181*51,752\)

\(Approximating:\)

\(=100*200*50,000\)

\(=10^2*2*100*5*10,000\)

\(=10^2*10^2*10^4*5*2\)

\(=10^2*10^2*10^4*10^1\)

\(=10^9\)

The answer is D
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The question asks for "units".

If we round the numbers, we have 100 regions * 200 stores/region * 50,000 units/store = 10^9 units


Here's a very similar question:

Question: https://gmatclub.com/forum/last-year-me ... l#p2105366
Solution: https://gmatclub.com/forum/last-year-me ... l#p3095151


Here's another question in which rounding and using the answer choices is helpful:

Question: https://gmatclub.com/forum/a-corporatio ... l#p1333975
Solution: https://gmatclub.com/forum/a-corporatio ... l#p3094235
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A certain manufacturer sells its products to stores in 113 different.png
A certain manufacturer sells its products to stores in 113 different.png [ 114.95 KiB | Viewed 12212 times ]

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Short video solution here (1:00):



 
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Bunuel
A certain manufacturer sells its products to stores in 113 different regions worldwide, with an average (arithmetic mean) of 181 stores per region. If last year these stores sold an average of 51,752 units of the manufacturer’s product per store, which of the following is closest to the total number of units of manufacturer’s product sold worldwide last year?

A) 10^6
B) 10^7
C) 10^8
D) 10^9
E) 10^10
­
We see that the question tests estimation since the options are all powers of 10 while the actual figures are quite large and random. 

Total number of units sold
\(= 113 * 181 * 51752 \)

\(= 100 * 200 * 50,000\)
\(= 2*5 * 10^8\)
\(= 10^9\)

Answer (D)

Video on Estimations:
https://youtu.be/4Wy7BrQrjkM ­
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