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A certain protective additive increases from 45 days to 60

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A certain protective additive increases from 45 days to 60  [#permalink]

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New post 27 May 2012, 09:50
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A certain protective additive increases from 45 days to 60 days the time between required maintenance checks on an industrial vehicle. By what percent is the time between maintenance checks increased by using the additive?

A. 25%
B. 33 1/3%
C. 50%
D. 66 2/3%
E. 75%
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Re: A certain protective additive increases from 45 days to 60  [#permalink]

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New post 28 May 2012, 00:50
macjas wrote:
A certain protective additive increases from 45 days to 60 days the time between required maintenance checks on an industrial vehicle. By what percent is the time between maintenance checks increased by using the additive?

A. 25%
B. 33 1/3%
C. 50%
D. 66 2/3%
E. 75%


General formula for percent increase or decrease, (percent change): \(percent=\frac{Change}{Original}*100\).

So, the time between maintenance checks increased by \(\frac{60-45}{45}*100=33\frac{1}{3}%\).

Answer: B.
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A certain protective additive increases from 45 days to 60  [#permalink]

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New post 17 May 2017, 06:22
A certain protective additive increases from 45 days to 60 days the time between required maintenance checks on an industrial vehicle. By what percent is the time between maintenance checks increased by using the additive?

A. 25%
B. 33 1/3%
C. 50%
D. 66 2/3%
E. 75%

Percentage Change = Change in value / Initial value x 100
Protective additive increases from 45 days to 60 days; Therefore Change = 60 - 45 = 15
Percentage Change = \(\frac{15}{45}\) x 100 = \(\frac{100}{3}\) = 33\(\frac{1}{3}\)%
Answer B...

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Re: A certain protective additive increases from 45 days to 60  [#permalink]

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New post 17 May 2017, 09:03
macjas wrote:
A certain protective additive increases from 45 days to 60 days the time between required maintenance checks on an industrial vehicle. By what percent is the time between maintenance checks increased by using the additive?

A. 25%
B. 33 1/3%
C. 50%
D. 66 2/3%
E. 75%


\(\frac{60 - 45}{45}*100\)

\(= \frac{15}{45}*100\)

\(= 33\)%

Thus, answer must be (B) \(33\frac{1}{3}\)%

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Re: A certain protective additive increases from 45 days to 60  [#permalink]

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New post 17 May 2017, 09:07
macjas wrote:
A certain protective additive increases from 45 days to 60 days the time between required maintenance checks on an industrial vehicle. By what percent is the time between maintenance checks increased by using the additive?

A. 25%
B. 33 1/3%
C. 50%
D. 66 2/3%
E. 75%

\(\frac{60 - 45}{45}*100\)

\(= \frac{15}{45}*100\)

\(= 33\)%

Thus, answer must be (B) \(33\frac{1}{3}\)%

_________________

Thanks and Regards

Abhishek....

PLEASE FOLLOW THE RULES FOR POSTING IN QA AND VA FORUM AND USE SEARCH FUNCTION BEFORE POSTING NEW QUESTIONS

How to use Search Function in GMAT Club | Rules for Posting in QA forum | Writing Mathematical Formulas |Rules for Posting in VA forum | Request Expert's Reply ( VA Forum Only )

Re: A certain protective additive increases from 45 days to 60 &nbs [#permalink] 17 May 2017, 09:07
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