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A certain right triangle has sides of length x, y, and z, [#permalink]

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07 Sep 2008, 08:15

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A certain right triangle has sides of length x, y, and z, where x < y < z. If the area of this triangular region is 1, which of the following indicates all of the possible values of y ? A. y > Sqrt (2) B. Sqrt (3)/ 2 < y < Sqrt(2) C. Sqrt(2)/3 < y < Sqrt (3)/ 2 D. Sqrt (3)/4 < y < Sqrt(2)/3 E. y < Sqrt (3)/4

As per my callcualtions value of y should be < Sqrt(2)?????????

A certain right triangle has sides of length x, y, and z, where x < y < z. If the area of this triangular region is 1, which of the following indicates all of the possible values of y ? A. y > Sqrt (2) B. Sqrt (3)/ 2 < y < Sqrt(2) C. Sqrt(2)/3 < y < Sqrt (3)/ 2 D. Sqrt (3)/4 < y < Sqrt(2)/3 E. y < Sqrt (3)/4

As per my callcualtions value of y should be < Sqrt(2)?????????

Z= hypotenus area 1=1/2 xy xy=2 as x<y then it is clearly y>1

options C,D,E are out.. because they contain values y<1..

between A and B. I can easily ruled out A. because it says y>sqrt(2)... which means it include .. large value... near 1 billion or greater also...

Will go for B.

What is OA.
_________________

Your attitude determines your altitude Smiling wins more friends than frowning

A certain right triangle has sides of length x, y, and z, where x < y < z. If the area of this triangular region is 1, which of the following indicates all of the possible values of y ? A. y > Sqrt (2) B. Sqrt (3)/ 2 < y < Sqrt(2) C. Sqrt(2)/3 < y < Sqrt (3)/ 2 D. Sqrt (3)/4 < y < Sqrt(2)/3 E. y < Sqrt (3)/4

As per my callcualtions value of y should be < Sqrt(2)?????????

A. y > sqrt2.

area = 1/2(xy) cuz z is hypotenous. therefore x and y must be p and b. 1= 1/2(xy) 2 = xy since xy = 2, and x < y, x and y cannot be equal but they are equal when each is sqrt2. since y > x, y should be > sqrt2.
_________________

A certain right triangle has sides of length x, y, and z, where x < y < z. If the area of this triangular region is 1, which of the following indicates all of the possible values of y ? A. y > Sqrt (2) B. Sqrt (3)/ 2 < y < Sqrt(2) C. Sqrt(2)/3 < y < Sqrt (3)/ 2 D. Sqrt (3)/4 < y < Sqrt(2)/3 E. y < Sqrt (3)/4

As per my callcualtions value of y should be < Sqrt(2)?????????

A

(1/2)*x*y = 1 x*y = 2

If x < y, then y must be greater than the value at which x = y and x*y = 2. This occurs at sqrt(2), so y must be greater than sqrt(2).

There is no upper bound for y. As y --> infininty, x --> 0 such that x*y = 2

A certain right triangle has sides of length x, y, and z, where x < y < z. If the area of this triangular region is 1, which of the following indicates all of the possible values of y ? A. y > Sqrt (2) B. Sqrt (3)/ 2 < y < Sqrt(2) C. Sqrt(2)/3 < y < Sqrt (3)/ 2 D. Sqrt (3)/4 < y < Sqrt(2)/3 E. y < Sqrt (3)/4

As per my callcualtions value of y should be < Sqrt(2)?????????

A

(1/2)*x*y = 1 x*y = 2

If x < y, then y must be greater than the value at which x = y and x*y = 2. This occurs at sqrt(2), so y must be greater than sqrt(2).

There is no upper bound for y. As y --> infininty, x --> 0 such that x*y = 2

YOU ARE RIGHT!! SILLY MISTAKE AGAIN.
_________________

Your attitude determines your altitude Smiling wins more friends than frowning