Bunuel wrote:

DarkKnight06 wrote:

A clock loses a minute every three hours for 4 days and gains 1% in the subsequent 6 days. If it was set right on Friday at 11 AM, what will be the time at the end of 10 days?

A. 11:54:40 AM

B. 11:56:24 AM

C. 12:16:40 PM

D. 11:54:24 AM

E. 12:06:36 PM

Clock loses: 1 minute in 3 hours = 8 minutes in 24 hours = 32 minutes in 4 days.

Clock gains: 1% in the subsequent 6 days = 1% in 6*24*60 minutes = 86.40 minute in 6 days;

Net gain in 10 days = 86.40 - 32 = 54.4 minutes.

11AM + 54.4 minutes = 11:54 and 4/10th of a minute or 24 seconds.

Answer: D.

After looking at your solution..it was easy to understand..but I tried something different..I can't figure out what's wrong with my solution..

In 4 days, the clock lost 32 minutes..converting it into percentage

\(\frac{32}{60*24*4} * 100\)

gives 0.55% ~ 0.5%

And then it gains 1% in the next 6 days..

so in total of ten days the time will become

(99.5 * 1.01) in %age terms..99.5 because it lost 0.5% in the first 4 days

= 100.49%

or 0.5% gain of the ten days' time

or

24*10*0.005

but no answer justifies this!

What am I doing wrong?

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