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A clock loses a minute every three hours for 4 days and gain

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DarkKnight06
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A clock loses a minute every three hours for 4 days and gain [#permalink] New post   03 Jul 2013, 22:42
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A clock loses a minute every three hours for 4 days and gains 1% in the subsequent 6 days. If it was set right on Friday at 11 AM, what will be the time at the end of 10 days?

A. 11:54:40 AM
B. 11:56:24 AM
C. 12:16:40 PM
D. 11:54:24 AM
E. 12:06:36 PM
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D
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Bunuel
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Re: A clock loses a minute every three hours for 4 days and gain [#permalink] New post   03 Jul 2013, 23:18
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DarkKnight06 wrote:
A clock loses a minute every three hours for 4 days and gains 1% in the subsequent 6 days. If it was set right on Friday at 11 AM, what will be the time at the end of 10 days?

A. 11:54:40 AM
B. 11:56:24 AM
C. 12:16:40 PM
D. 11:54:24 AM
E. 12:06:36 PM


Clock loses: 1 minute in 3 hours = 8 minutes in 24 hours = 32 minutes in 4 days.
Clock gains: 1% in the subsequent 6 days = 1% in 6*24*60 minutes = 86.40 minute in 6 days;

Net gain in 10 days = 86.40 - 32 = 54.4 minutes.

11AM + 54.4 minutes = 11:54 and 4/10th of a minute or 24 seconds.

Answer: D.
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jjack0310
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Re: A clock loses a minute every three hours for 4 days and gain [#permalink] New post   12 Aug 2013, 19:23
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Its kinda confusing what exactly 1% is referring to.
1% minute?
1% hours?

Bunuel's explanation makes sense if you say the gain is 1% minutes but how do you know 1% not hours?
I guess, the question would be consistent and thus 1% has to refer to minutes, but still...
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Re: A clock loses a minute every three hours for 4 days and gain [#permalink] New post   13 Aug 2013, 01:58
Expert Reply
jjack0310 wrote:
Its kinda confusing what exactly 1% is referring to.
1% minute?
1% hours?

Bunuel's explanation makes sense if you say the gain is 1% minutes but how do you know 1% not hours?
I guess, the question would be consistent and thus 1% has to refer to minutes, but still...


Given: a clock gains 1% in 6 days, so it gains 1% of 6 days --> clock gains: 1% in 6*24*60 minutes = 86.40 minute in 6 days;
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Re: A clock loses a minute every three hours for 4 days and gain [#permalink] New post   13 Aug 2013, 04:19
DarkKnight06 wrote:
A clock loses a minute every three hours for 4 days and gains 1% in the subsequent 6 days. If it was set right on Friday at 11 AM, what will be the time at the end of 10 days?

A. 11:54:40 AM
B. 11:56:24 AM
C. 12:16:40 PM
D. 11:54:24 AM
E. 12:06:36 PM

Loses 8 minutes each day.
so total loss = 4×8 = 32min

subsequent 6 days = 6×24×60 minutes
1% gain = ( 6×24×60)/100 = 86.4 minutes

so, total gain = 86.4 - 32 = 54.4 min = 54 + 0.4 min = 54 minutes + 0.4 × 60 seconds = 54min + 24seconds

10 days later the clock should be 54 min and 24seconds fast.
so time , 11:54:24 am (Answer D)
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Re: A clock loses a minute every three hours for 4 days and gain [#permalink] New post   13 Aug 2013, 13:24
Bunuel wrote:
jjack0310 wrote:
Its kinda confusing what exactly 1% is referring to.
1% minute?
1% hours?

Bunuel's explanation makes sense if you say the gain is 1% minutes but how do you know 1% not hours?
I guess, the question would be consistent and thus 1% has to refer to minutes, but still...


Given: a clock gains 1% in 6 days, so it gains 1% of 6 days --> clock gains: 1% in 6*24*60 minutes = 86.40 minute in 6 days;


I understand the answer. I got the same result, but only after I looked at your solution as to what 1% was referring to. But thanks anyways.
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Re: A clock loses a minute every three hours for 4 days and gain [#permalink] New post   11 Dec 2014, 06:20
Its not that hard once someone figures out what 1% refers to...which well it should be a little clearer
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Re: A clock loses a minute every three hours for 4 days and gain [#permalink] New post   07 Nov 2016, 00:00
Bunuel wrote:
DarkKnight06 wrote:
A clock loses a minute every three hours for 4 days and gains 1% in the subsequent 6 days. If it was set right on Friday at 11 AM, what will be the time at the end of 10 days?

A. 11:54:40 AM
B. 11:56:24 AM
C. 12:16:40 PM
D. 11:54:24 AM
E. 12:06:36 PM


Clock loses: 1 minute in 3 hours = 8 minutes in 24 hours = 32 minutes in 4 days.
Clock gains: 1% in the subsequent 6 days = 1% in 6*24*60 minutes = 86.40 minute in 6 days;

Net gain in 10 days = 86.40 - 32 = 54.4 minutes.

11AM + 54.4 minutes = 11:54 and 4/10th of a minute or 24 seconds.

Answer: D.

After looking at your solution..it was easy to understand..but I tried something different..I can't figure out what's wrong with my solution..

In 4 days, the clock lost 32 minutes..converting it into percentage
\(\frac{32}{60*24*4} * 100\)

gives 0.55% ~ 0.5%

And then it gains 1% in the next 6 days..
so in total of ten days the time will become
(99.5 * 1.01) in %age terms..99.5 because it lost 0.5% in the first 4 days

= 100.49%
or 0.5% gain of the ten days' time
or
24*10*0.005

but no answer justifies this!

What am I doing wrong?
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Re: A clock loses a minute every three hours for 4 days and gain [#permalink] New post   31 May 2018, 11:46
Gotta agree that it is not clear at all what 1% means
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Re: A clock loses a minute every three hours for 4 days and gain [#permalink] New post   01 Jun 2018, 11:22
Expert Reply
DarkKnight06 wrote:
A clock loses a minute every three hours for 4 days and gains 1% in the subsequent 6 days. If it was set right on Friday at 11 AM, what will be the time at the end of 10 days?

A. 11:54:40 AM
B. 11:56:24 AM
C. 12:16:40 PM
D. 11:54:24 AM
E. 12:06:36 PM



Since there are 4 x 24 = 96 hours in four days, the clock loses 96/3 = 32 minutes in the first 4 days.

In the next 6 days, the clock gains 0.01 x (6 x 24) = 1.44 hours = 86.4 minutes = 86 minutes and 24 seconds

Subtracting 32 minutes from the gain we have that the clock gains:

54 minutes and 24 seconds

Thus, the clock will now read 11:54:24 AM.

Answer: D
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Re: A clock loses a minute every three hours for 4 days and gain [#permalink] New post   06 Jan 2024, 00:46
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Re: A clock loses a minute every three hours for 4 days and gain [#permalink]
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