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13 Dec 2017, 00:20
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
59% (02:04) correct
41%
(02:12)
wrong
based on 278
sessions
History
Date
Time
Result
Not Attempted Yet
A clothing retailer bought 2 shipments of equal numbers of dresses at the same price. When the first shipment was sold in its entirety at $70 per dress, it generated $1,600 in profits. When the retailer sold the second shipment in its entirety at $90 per dress, it generated $2,400 in profits. What was the total number of dresses in both shipments?
(A) 40
(B) 50
(C) 60
(D) 80
(E) 100
(A) 40
(B) 50
(C) 60
(D) 80
(E) 100
Lets say there were x number of dresses in each shipment. And cost of the each dress is y. Then we can set up following equation:
70x - xy = 1600
90x -xy = 2400
20x = 800
x= 40
Therefore there are 80 dresses in both shipments
70x - xy = 1600
90x -xy = 2400
20x = 800
x= 40
Therefore there are 80 dresses in both shipments
13 Dec 2017, 05:22
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Two shipments equal number of dress, Let dress be x , y be the price of each dress
1. Given 70x = 1600 + xy
2. Given 90x =2400+xy
(note 1600 and 2400 is the profit) Equate with xy
90x-2400=70x-1600
20x =800
x= 40
The question is total number of shpments, so it is 40+40 = 80
Ans : D
1. Given 70x = 1600 + xy
2. Given 90x =2400+xy
(note 1600 and 2400 is the profit) Equate with xy
90x-2400=70x-1600
20x =800
x= 40
The question is total number of shpments, so it is 40+40 = 80
Ans : D
