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09 Jul 2025, 02:34
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Difficulty:
55%
(hard)
Question Stats:
72% (02:34) correct
28%
(03:01)
wrong
based on 186
sessions
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A container has a mixture of milk and water in the ratio 3:1. After removing 20 liters of the mixture and adding 12 liters of water, the new ratio of milk to water becomes 2:1. What is the total volume of the original mixture?
A. 36
B. 54
C. 72
D. 92
E. 116
A. 36
B. 54
C. 72
D. 92
E. 116
Let's say the initial volume is x liters in total and we are given that Milk : Water :: 3 : 1
that means in 4 qty of total volume 3 qty is milk and 1 qty is water. So, for x qty -->
Milk = 3x/4
Water = x/4
Removing 20 liters of the mixture and adding 12 liters of water
Remember: we are removing from the mix. So, this 20 liter will have the same ratio of Milk to Water as the whole mixture = 3 : 1
That means we are removing 15 liters of milk and 5 liters of Water
Then we are adding 12 liters of water only.
resulting in
Milk = 3x/4 - 15
Water = x/4 - 5 + 12 = x/4 +7
We know that this Milk to Water ratio is 2:1 so,
( 3x/4 - 15 ) / (x/4 +7) = 2/1
3x/4 - 15 = x/2 + 14
x = 116
that means in 4 qty of total volume 3 qty is milk and 1 qty is water. So, for x qty -->
Milk = 3x/4
Water = x/4
Removing 20 liters of the mixture and adding 12 liters of water
Remember: we are removing from the mix. So, this 20 liter will have the same ratio of Milk to Water as the whole mixture = 3 : 1
That means we are removing 15 liters of milk and 5 liters of Water
Then we are adding 12 liters of water only.
resulting in
Milk = 3x/4 - 15
Water = x/4 - 5 + 12 = x/4 +7
We know that this Milk to Water ratio is 2:1 so,
( 3x/4 - 15 ) / (x/4 +7) = 2/1
3x/4 - 15 = x/2 + 14
x = 116
General Discussion
09 Jul 2025, 05:44
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Explain how to solve this question
