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13 Jun 2016, 03:28
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
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Question Stats:
86% (01:18) correct
14%
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A cube has three of its faces painted half red, half white. The other three faces are completely painted white. What is the ratio between the total red painted and the total white painted areas of the cube?
A. 1:6
B. 3:6
C. 1:2
D. 1:4.5
E. 1:3
A. 1:6
B. 3:6
C. 1:2
D. 1:4.5
E. 1:3
13 Jun 2016, 05:32
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total faces = 6
3 faces painted half red and half white, while rest are white
ratio of total red/total white = (3*0.5)/(3*0.5)+3 = 1.5/4.5 = 1/3
3 faces painted half red and half white, while rest are white
ratio of total red/total white = (3*0.5)/(3*0.5)+3 = 1.5/4.5 = 1/3
13 Jun 2016, 06:59
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Bunuel
Area of each face is equal since its a cube. Lets say area of each face= x
area painted red= x/2+x/2+x/2= 3x/2
area painted white= x+x+x+x/2+x/2+x/2= 9x/2
ratio= 3x/2/9x/2= 1/3
E is the answer
