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01 Jun 2026, 14:45
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A data-entry clerk entered all records from several client files in one day. If the clerk entered 480 records in total that day, was the average (arithmetic mean) time per record less than 45 seconds?
(1) It took no more than 24 minutes to enter all the records from any one client file.
(2) The records entered that day came from 12 client files.
The OA will be automatically revealed on Thursday 4th of June 2026 02:45:12 PM Pacific Time Zone
(1) It took no more than 24 minutes to enter all the records from any one client file.
(2) The records entered that day came from 12 client files.
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The OA will be automatically revealed on Thursday 4th of June 2026 02:45:12 PM Pacific Time Zone
BongBideshini
Joined: 25 May 2021
Last visit: 02 Jun 2026
Posts: 278
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Concentration: Entrepreneurship, Marketing
Schools: HBS '27 Stanford '27 Wharton '27 Sloan '27
GPA: 3.8
WE:Engineering (Government)
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01 Jun 2026, 20:44
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We need to know whether the average time per record was less than 45 seconds.
Since there were 480 records, this is equivalent to asking whether the total time was less than:
480 × 45 = 21,600 seconds = 360 minutes.
So the question becomes:
Was the total time less than 360 minutes?
Statement (1):
It took no more than 24 minutes to enter all the records from any one client file.
We do not know how many client files there were.
If there were 10 client files, the total time could be at most 10 × 24 = 240 minutes (<360 minutes)
If there were 20 client files, the total time could be as much as 20 × 24 = 480 minutes. (>360 minutes.)
Statement (1) is not sufficient.
Statement (2):
The records came from 12 client files.
We know the number of files, but we do not know how long each file took.
Statement (2) is not sufficient.
Statements (1) and (2) together:
There were 12 files, and each took no more than 24 minutes.
Therefore, the total time was at most:
12 × 24 = 288 minutes.
Since 288 < 360, the average time per record must have been less than 45 seconds.
Both statements together are sufficient.
Answer: C
Since there were 480 records, this is equivalent to asking whether the total time was less than:
480 × 45 = 21,600 seconds = 360 minutes.
So the question becomes:
Was the total time less than 360 minutes?
Statement (1):
It took no more than 24 minutes to enter all the records from any one client file.
We do not know how many client files there were.
If there were 10 client files, the total time could be at most 10 × 24 = 240 minutes (<360 minutes)
If there were 20 client files, the total time could be as much as 20 × 24 = 480 minutes. (>360 minutes.)
Statement (1) is not sufficient.
Statement (2):
The records came from 12 client files.
We know the number of files, but we do not know how long each file took.
Statement (2) is not sufficient.
Statements (1) and (2) together:
There were 12 files, and each took no more than 24 minutes.
Therefore, the total time was at most:
12 × 24 = 288 minutes.
Since 288 < 360, the average time per record must have been less than 45 seconds.
Both statements together are sufficient.
Answer: C
Bunuel
01 Jun 2026, 23:48
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Given: no fo records n= 480 records in total that day,
To Find: Average record time "ta" per record <45 sec.. ie, total time to record T/number of records n=480) "ta" <45
(1) Per client file time taken<24min or 24*60sec
but total number of client files is not know to find T. Hence insufficient
(2) number of files =12. But we have no info on time with only this choice. Hence insufficient
Considering both, we get ta<12*24*60/480 so ta<36 sec. Hence we can answer the question.
Answer is C
To Find: Average record time "ta" per record <45 sec.. ie, total time to record T/number of records n=480) "ta" <45
(1) Per client file time taken<24min or 24*60sec
but total number of client files is not know to find T. Hence insufficient
(2) number of files =12. But we have no info on time with only this choice. Hence insufficient
Considering both, we get ta<12*24*60/480 so ta<36 sec. Hence we can answer the question.
Answer is C
