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fitzpratik
Posts: 224
26 Dec 2018, 01:47
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
81% (00:53) correct
19%
(01:52)
wrong
based on 127
sessions
History
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A fair coin is tossed 5 times. What is the probability that the fourth toss would turn a head?
A. \(\frac{1}{5P3}\)
B.\(\frac{1}{5P9}\)
C. \(\frac{1}{2}\)
D. \(\frac{1}{3}\)
E. \(\frac{1}{2^3}\)
A. \(\frac{1}{5P3}\)
B.\(\frac{1}{5P9}\)
C. \(\frac{1}{2}\)
D. \(\frac{1}{3}\)
E. \(\frac{1}{2^3}\)
26 Dec 2018, 02:04
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fitzpratik
The probability doesn't chnage its 50% with all turns
26 Dec 2018, 09:17
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Solution
Given:
- • A fair coin is tossed 5 times
To find:
- • The probability that the fourth toss will be a head
Approach and Working:
We know for the toss of a fair coin,
- • Probability of a head = \(\frac{1}{2}\)
• Probability of a tail = \(\frac{1}{2}\)
In case one fair coin is tossed multiple number of times, each of the outcomes are independent of the other outcomes.
Therefore, the probability of getting a head in the fourth toss = \(\frac{1}{2}\)
Hence, the correct answer is option C.
Answer: C
