apoorvmht
A financial adviser was showing a client the value, rounded to the nearest cent, of an initial investment of $100.00 after 5, 10, 15, 20, 25, and 30 years, under the assumption that the value increases by r% per year for some positive constant r. The adviser correctly gave $130.01 for the value after 5 years. However, the adviser inadvertently made two transcription errors, and as a result, two of the remaining values shown to the client were incorrect.
Assuming the options provided are the remaining five amounts shown to the client, select for First error the lesser of the two incorrectly transcribed values and select for Second error the greater of the two incorrectly transcribed values. Make only two selections, one in each column.
So, we are looking at compound interest at r% per year.
Finding r here would be cumbersome, So, let us take rate of interest as R for a time period of 5 years as we are talking of amount after every five years.
So, if time period is 5 years, the R is \(\frac{130.01-100}{100}*100\) or 30.01%
10 years: After another 5 years, amount will become \(130.01*(1+\frac{30.01}{100})=130.01*1.3001\)~\(169\neq 160\)
15 years: After another 5 years, amount will become \(169*(1+\frac{30.01}{100})=169*1.3001\)~\(219\)
20 years: After another 5 years, amount will become \(219*(1+\frac{30.01}{100})=219*1.3001\)~\(285\)
25 years: After another 5 years, amount will become \(285*(1+\frac{30.01}{100})=285*1.3001\)~\(371\neq 317\)
30 years: After another 5 years, amount will become \(371*(1+\frac{30.01}{100})=371*1.3001\)~\(482\)
The values are 160 and 317
Mathematically
CI formula \(P(1+\frac{r}{100})^t=Amount\)
\(100(1+\frac{r}{100})^5=130.01\)
\((1+\frac{r}{100})^5=1.3001\)
After 10 years: \(100(1+\frac{r}{100})^10\)
\(100((1+\frac{r}{100})^5)^2=130.01*(1+\frac{r}{100})^5=130.01*1.3001\)
And so on