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# A five-member committee is to be formed from a group of five

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Intern
Joined: 22 Oct 2007
Posts: 3
A five-member committee is to be formed from a group of five [#permalink]

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20 Sep 2008, 18:03
A five-member committee is to be formed from a group of five military officers and nine civilians. If the committee must include at least two officers and two civilians, in how many different ways can the committee be chosen?
thanks

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Intern
Joined: 02 Sep 2008
Posts: 45
Re: Help with a Combination Problem [#permalink]

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20 Sep 2008, 18:39
We are forming committee of 5 people from 5 military and 9 civilians. Also, the committee must form of at least 2 military personels and 2 civilians.

Lets form a team,
One team is 2 military personels and 3 civilians.
And, another team is 3 military personnels and 2 civilians.

So total team:
5C2 * 9C3 + 9C2 * 5C3 = 10 * 84 + 10 * 36
= 840 + 360
= 1, 200
VP
Joined: 30 Jun 2008
Posts: 1008
Re: Help with a Combination Problem [#permalink]

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20 Sep 2008, 21:28
kidboc1 wrote:
A five-member committee is to be formed from a group of five military officers and nine civilians. If the committee must include at least two officers and two civilians, in how many different ways can the committee be chosen?
thanks

Remember this -> When you have AND you MULTIPLY and when you have OR, you ADD

CASE1 -> we choose 3 out of 5 military officials AND 2 out of 9 civilians => 5C3 * 9C2

OR

CASE2 -> we choose 2 out of 5 military officials AND 3 out of 9 civilians => 5C2 * 9C3

So here CASE1 OR CASE2 = > 5C3*9C2 + 5C2*9C3 = 1200

Hope that helps
_________________

"You have to find it. No one else can find it for you." - Bjorn Borg

Director
Joined: 20 Sep 2006
Posts: 631
Re: Help with a Combination Problem [#permalink]

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22 Sep 2008, 14:47
I was trying to solve it this way:

We need 5 people commitee:

# of way 2 officer can be choosen = 5 x 4
# of ways 2 citizens can be choosen = 9 x 8
# of ways the 5th person can be choosen = 5+9 (total ppl) - 4 (ppl already choosed) = 10

there total number of ways = (5 * 4 * 9 * 8 * 10) / 5 * 4 * 3 * 2 * 1 = 120

Can somebody please tell .. where am I missing the logic?

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This is not a quality discussion. It has been retired.

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Re: Help with a Combination Problem   [#permalink] 22 Sep 2008, 14:47
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# A five-member committee is to be formed from a group of five

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