Hi AmishaJ,Your instinct comes from the phrase
"the price of each cheese is proportional to its weight," which makes it sound like weight needs to be built into the equation in some special, extra way. That's the exact spot to fix.
"Proportional to weight" is already fully captured by writing weight × price-per-pound. Let S = price of
1 pound of Stilton and M = price of
1 pound of Manchego. Because price scales evenly with weight:
- cost of Stilton = (pounds) × S
- cost of Manchego = (pounds) × M
So Customer A gives
15S +
3.75M =
438. The number of pounds (
15 and
3.75)
is the count per type - it's the multiplier sitting right in front of each price. You are already taking it into account.
Where the double-counting creeps in: if you also divide the price by the weight (like writing
5 × (
5S/
15)), you're inserting the weight a second time. Weight belongs in the equation exactly
once - as the multiplier. The per-pound price itself is a fixed constant; it does not change as you buy more.
A quick everyday checkSay apples cost
$2 per pound (a constant). Then:
-
3 pounds cost
3 ×
$2 =
$6-
5 pounds cost
5 ×
$2 =
$10The weight appears once as the multiplier. Nobody writes
3 × (
3 ×
$2) - that would count the
3 pounds twice and give the wrong total.
Same here: each customer's equation is just (pounds of Stilton)·S + (pounds of Manchego)·M = total. Once you set them up that plain way, Statement (
1) gives a genuinely new equation (so you can solve for M), while Statement (
2) collapses back into Customer A's equation - which is why the answer is
A.
Answer: AAmishaJ
Why are we NOT taking into account - the number of cheese per type?