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Sajjad1994
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By looking at the radius and height of both the pipes, area of outlet would 2 times area of inlet:

R(Outlet) = 4/5 R(Inlet)
Height (Outlet)=2.5 (Inlet)

Area (Outlet) = 4/5*2.5 (Area of Inlet) = 2 (Area of Inlet)

We can cancel last 2 option s(15000,18000) and need to calculate only one area and just double or half to get the other one.
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2piRL
Area=piDL

Cost Intake=5Area=1000pi=3140$

Cost Outlet=5Area=2000pi=6280$
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How did you take π to be 3?
Sajjad1994
Official Explanation

The trick here is that, when finding the surface area of the pipe, we don’t have to find the area of the circle on the top or the bottom of the cylinder. Since the pipe is open, we only need to find the surface area of the rectangular portion that makes up the surface of the pipe: \(2πrh.\) For the intake pipe, the radius is 5 and the length is 20, so its surface area is \(2 * π * 5 * 20\), which gives a surface area of \(200π\) square meters. Since our values are fairly spread out, we can estimate \(π\) as 3 to give us a total surface area of 600 square meters. At $5 per square meter, the total cost will be \(600 * 5 = $3,000\). For the outlet pipe, the surface area is \(2 * π * 4 * 50\), or \(400π. 400 * 3\) gives us a surface area of roughly 1200 square meters, so the cost will be \(1200 * 5 = $6,000.\)

Intake Pipe: $3,000
Outlet Pipe: $6,000
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MintLog
How did you take π to be 3?

We are asked for the approximate cost, so \(\pi\) can be estimated as 3. Using 3.14 would give slightly more precise values, but the same answer choices would still be selected.
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