rrsnathan wrote:

A Man walked from his house to office at 5kmph and got 20 minutes late. if he had travelled at 7.5kmph, he would have reached 12 minutes early. The distance from his house to office is?

A) 4Km

B) 16Km

C) 8Km

D) 9Km

E) 12Km

Let the original distance and time be D & t

Case 1 - If man travels at 5kmph, he reaches late 20 min or 1/3 hr

We can write the same as

\(\frac{D}{5}\) = t + \(\frac{1}{3}\) -----(1)

Case 2 - If man travels at 7.5kmph, he reaches early 12 min or 1/5 hr

We can write the same as

\(\frac{D}{7.5}\) = t - \(\frac{1}{5}\) -----(2)

Solving both we get D = 8

Answer C

_________________

If you like my Question/Explanation or the contribution, Kindly appreciate by pressing KUDOS.

Kudos always maximizes GMATCLUB worth -Game Theory

If you have any question regarding my post, kindly pm me or else I won't be able to reply