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A manager must select 2 people from a group of 4 employees. One person

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A manager must select 2 people from a group of 4 employees. One person [#permalink]

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A manager must select 2 people from a group of 4 employees. One person will be the shop steward and the other person will be the treasurer. In how many different ways can this be accomplished?

(A) 2

(B) 6

(C) 8

(D) 12

(E) 16
[Reveal] Spoiler: OA

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Re: A manager must select 2 people from a group of 4 employees. One person [#permalink]

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New post 17 Aug 2017, 00:46
4C2 = 6

Hence total possible ways of selection = 6
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Re: A manager must select 2 people from a group of 4 employees. One person [#permalink]

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New post 17 Aug 2017, 01:14
Bunuel wrote:
A manager must select 2 people from a group of 4 employees. One person will be the shop steward and the other person will be the treasurer. In how many different ways can this be accomplished?

(A) 2

(B) 6

(C) 8

(D) 12

(E) 16


4C2 * 2 = 6 * 2 = 12
4C2 for selection and multiplication by 2 for allocation
D
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Re: A manager must select 2 people from a group of 4 employees. One person [#permalink]

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New post 18 Aug 2017, 10:06
12--> 6 ways to select and 2 ways to shuffle
What is OA?
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Re: A manager must select 2 people from a group of 4 employees. One person [#permalink]

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New post 18 Aug 2017, 10:43
Luckisnoexcuse wrote:
Bunuel wrote:
A manager must select 2 people from a group of 4 employees. One person will be the shop steward and the other person will be the treasurer. In how many different ways can this be accomplished?

(A) 2

(B) 6

(C) 8

(D) 12

(E) 16


4C2 * 2 = 6 * 2 = 12
4C2 for selection and multiplication by 2 for allocation
D

Mine approach would be the same as yours.
OA ???

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Re: A manager must select 2 people from a group of 4 employees. One person [#permalink]

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New post 18 Aug 2017, 10:49
kumarparitosh123 wrote:
Luckisnoexcuse wrote:
Bunuel wrote:
A manager must select 2 people from a group of 4 employees. One person will be the shop steward and the other person will be the treasurer. In how many different ways can this be accomplished?

(A) 2

(B) 6

(C) 8

(D) 12

(E) 16


4C2 * 2 = 6 * 2 = 12
4C2 for selection and multiplication by 2 for allocation
D

Mine approach would be the same as yours.
OA ???

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The OA will be automatically revealed on Thursday 24th of August 2017 01:18:15 AM Pacific Time Zone
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Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


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Re: A manager must select 2 people from a group of 4 employees. One person [#permalink]

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New post 18 Aug 2017, 10:56
Bunuel wrote:
A manager must select 2 people from a group of 4 employees. One person will be the shop steward and the other person will be the treasurer. In how many different ways can this be accomplished?

(A) 2

(B) 6

(C) 8

(D) 12

(E) 16


Here we need to assign / arrange \(2\) people out of \(4\) people to \(2\) posts.

This can be done is \(4_P_2\) ways \(= 12\)

Option D
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Re: A manager must select 2 people from a group of 4 employees. One person [#permalink]

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New post 18 Aug 2017, 11:38
Why combination and not permutation


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A manager must select 2 people from a group of 4 employees. One person [#permalink]

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New post 18 Aug 2017, 13:26
Approach could be first select two person out of 4 and then arrange them.

Select 2 person out of 4 people= \(4C2\)
number of ways to arrange two selected person into 2 positions =2

Answer would be 4C2*2= 12

IMO:D
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Re: A manager must select 2 people from a group of 4 employees. One person [#permalink]

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New post 18 Aug 2017, 14:49
Hello
Out of 4 people, 2 people can be selected in 4C2 number of ways
also, two persons selected for two positions can be shuffled in 2! ways as A-B, B-A
So total number of ways = 4C2*2! = 6*2 = 12
Hence Option D
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Re: A manager must select 2 people from a group of 4 employees. One person [#permalink]

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New post 18 Aug 2017, 16:28
Ans - D
Easy way:
Assume that there are 2 slots to be filled, S-Steward and T-Treasurer
For S - You have 4 people to chose from
Once, S is selected, for T, you are left with 3 people to chose from

So, total options - 4x3 = 12

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Re: A manager must select 2 people from a group of 4 employees. One person [#permalink]

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New post 18 Aug 2017, 18:54
selection one 1 out of 4
4 ways
selection 1 out of 3
3 ways
total 4*3=12
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Re: A manager must select 2 people from a group of 4 employees. One person [#permalink]

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New post 19 Aug 2017, 02:39
D) 12
total number of way for selecting 2 out of 4 = 4c1 * 3c1= 4*3 =12
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Re: A manager must select 2 people from a group of 4 employees. One person [#permalink]

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New post 24 Aug 2017, 03:46
Option:D
For position 1
4 choices we have
for position 2
3 choices we have
4*3=
12
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Re: A manager must select 2 people from a group of 4 employees. One person [#permalink]

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New post 24 Aug 2017, 12:46
Bunuel wrote:
A manager must select 2 people from a group of 4 employees. One person will be the shop steward and the other person will be the treasurer. In how many different ways can this be accomplished?

(A) 2

(B) 6

(C) 8

(D) 12

(E) 16


Since we have specific positions in the group, order matters, and so we have a permutation. Thus, the number of ways to select a steward and a treasurer from 4 employees is 4P2 = 4!/2! = 4 x 3 = 12 ways.

Answer: D
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Re: A manager must select 2 people from a group of 4 employees. One person   [#permalink] 24 Aug 2017, 12:46
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