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A mixture of oil, water, and vinegar contains 10% oil. After all of th

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A mixture of oil, water, and vinegar contains 10% oil. After all of th  [#permalink]

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New post 23 Aug 2015, 12:55
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A mixture of oil, water, and vinegar contains 10% oil. After all of the water evaporates, what percent of the mixture is oil?

(1) Before the water evaporated, the mixture exactly filled a one liter bottle.

(2) Before the water evaporated, vinegar accounted for forty percent of the mixture.

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Re: A mixture of oil, water, and vinegar contains 10% oil. After all of th  [#permalink]

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New post 23 Aug 2015, 17:48
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shasadou wrote:
A mixture of oil, water, and vinegar contains 10% oil. After all of the water evaporates, what percent of the mixture is oil?

(1) Before the water evaporated, the mixture exactly filled a one liter bottle.

(2) Before the water evaporated, vinegar accounted for forty percent of the mixture.


Let L,V and W stand for proportions of oil, vinegar and water in the mixture. Given, L/T = 0.1 ---> L = 0.1T. % of L when all water evaporates ---> w=0 --> L/(L+V) = ?

Per statement 1, T=1 liter. Does not provide any information about the proportion of vinegar in the mixture. Not sufficient.

Per statement 2, V = 0.4T ----> ratio : L/(L+0.4T) and from L=0.1T ---> ratio = 0.1T/(0.1T+0.4T) ---> thus you get a sufficient answer. B is sufficient to answer.

B is the correct answer.
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Re: A mixture of oil, water, and vinegar contains 10% oil. After all of th  [#permalink]

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New post 16 Sep 2018, 18:19
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shasadou wrote:
A mixture of oil, water, and vinegar contains 10% oil. After all of the water evaporates, what percent of the mixture is oil?

(1) Before the water evaporated, the mixture exactly filled a one liter bottle.

(2) Before the water evaporated, vinegar accounted for forty percent of the mixture.


\({\text{Before: x}}\,\,{\text{liters}}\,\,\,\,\left\{ \begin{gathered}
{\text{oil}}\,\,:0.1x\,\,{\text{liters}} \hfill \\
water\,\,:\,\,k\left( {0.9x} \right)\,\,{\text{liters}} \hfill \\
vinegar\,\,:\,\,\,\left( {1 - k} \right)\left( {0.9x} \right)\,\,{\text{liters}}\,\, \hfill \\
\end{gathered} \right.\,\,\,\,\,\,\,\left( {0 < k < 1} \right)\)

\({\text{After}}:\,\,\,{\text{x}}\left( {1 - 0.9k} \right)\,\,\,{\text{liters}}\,\,\,\left\{ \begin{gathered}
{\text{oil}}\,\,:0.1x\,\,{\text{liters}} \hfill \\
water\,\,:\,\,0\,\,{\text{liters}} \hfill \\
vinegar\,\,:\,\,\,\left( {1 - k} \right)\left( {0.9x} \right)\,\,{\text{liters}}\,\, \hfill \\
\end{gathered} \right.\)

\(? = \frac{{0.1x}}{{x\left( {1 - 0.9k} \right)}} = \frac{{0.1}}{{1 - 0.9k}}\,\,\,\,\, \Leftrightarrow \,\,\,\,\,\boxed{? = k}\,\)

\(\left( 1 \right)\,\,\,x = 1\,\,\,\left\{ \begin{gathered}
\,{\text{Take}}\,\,\,k = 0.1 \hfill \\
\,{\text{Take}}\,\,\,k = 0.2 \hfill \\
\end{gathered} \right.\,\,\,\,\,\, \Rightarrow \,\,\,\,\,{\text{INSUFF}}.\)

\(\left( 2 \right)\,\,\,\,\,\frac{{\left( {1 - k} \right)\left( {0.9x} \right)\,\,}}{x} = \frac{2}{5}\,\,\,\,\, \Rightarrow \,\,\,\,k\,\,{\text{unique}}\,\,\,\,\, \Rightarrow \,\,\,\,{\text{SUFF}}.\,\)


This solution follows the notations and rationale taught in the GMATH method.

Regards,
Fabio.
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Re: A mixture of oil, water, and vinegar contains 10% oil. After all of th  [#permalink]

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New post 02 Oct 2018, 05:33
Since the mixture contains oil, water, and vinegar of which 10% is oil. So, 90% is water+vinegar.
When water evaporates only water+vinegar remains.
From stat 1 we cannot conclude the volume of vinegar hence not suff.
In stat 2 we are given % of vinegar. So we can say that since water=50% ,vinegar=40% and oil=10%
when water evaporates we can calculate % of oil.Hence B is correct choice.
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Re: A mixture of oil, water, and vinegar contains 10% oil. After all of th  [#permalink]

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New post 09 Jan 2019, 11:33
Gladiator59

Hey gladi could you please shed some light on my issue on this one?
My query is that do the proportions remain the same after water evaporation? I mean beforehand vinegar accounted for 40% of the mixture and oil 10% but after the water is evaporated will it still account for 40% ?

For instance lets say a mixture which is consisted of a, b and c liquids a=5 b=4 c=5 at first b accounts for 40% of the mixture a+b+c but when c is removed b accounts for 80% of the mixture.
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Re: A mixture of oil, water, and vinegar contains 10% oil. After all of th  [#permalink]

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New post 09 Jan 2019, 11:48
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Hi there UNSTOPPABLE12,

To answer your question - No. Think of it like this - Statement B says that Vinegar is 40% while oil is 10%.. so water will be the remaining or 50% of the mixture.

Assuming that only water evaporates - only vinegar and oil will remain...
So now vinegar will be 40% out of 50% total or Vinegar will be 80% of the new mixture whereas oil will be 20%. Their relative percentages double as the mixture becomes half of original

Hope it is clear.

UNSTOPPABLE12 wrote:
Gladiator59

Hey gladi could you please shed some light on my issue on this one?
My query is that do the proportions remain the same after water evaporation? I mean beforehand vinegar accounted for 40% of the mixture and oil 10% butafter the water is evaporated will it still account for 40% ?

For instance lets say a mixture which is consisted of a, b and c liquids a=5 b=4 c=5 at first b accounts for 40% of the mixture a+b+c but when c is removed b accounts for 80% of the mixture.

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Re: A mixture of oil, water, and vinegar contains 10% oil. After all of th  [#permalink]

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New post 09 Jan 2019, 12:26
Gladiator59 wrote:
Hi there UNSTOPPABLE12,

To answer your question - No. Think of it like this - Statement B says that Vinegar is 40% while oil is 10%.. so water will be the remaining or 50% of the mixture.

Assuming that only water evaporates - only vinegar and oil will remain...
So now vinegar will be 40% out of 50% total or Vinegar will be 80% of the new mixture whereas oil will be 20%. Their relative percentages double as the mixture becomes half of original

Hope it is clear.

UNSTOPPABLE12 wrote:
Gladiator59

Hey gladi could you please shed some light on my issue on this one?
My query is that do the proportions remain the same after water evaporation? I mean beforehand vinegar accounted for 40% of the mixture and oil 10% butafter the water is evaporated will it still account for 40% ?

For instance lets say a mixture which is consisted of a, b and c liquids a=5 b=4 c=5 at first b accounts for 40% of the mixture a+b+c but when c is removed b accounts for 80% of the mixture.


Gladiator59

Thanks gladi brilliant remarks as usual.
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Re: A mixture of oil, water, and vinegar contains 10% oil. After all of th   [#permalink] 09 Jan 2019, 12:26
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