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555-605 Level|   Graphs|   Non-Math Related|                  
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1. Children: 20% + teenagers 25%
Seniors= 17%
45/17= 2.65~

2. 540 people = difference of (23%+25%+20%= 68%)- 32% = 36%
36% is 540 people then total = 540/36%= 1500
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Official Explanation

1. The census indicates that______________times as many residents were children or teenagers as were seniors.

According to the graph, 45% of the residents were children or teenagers and 17% were seniors. Therefore there were 45/17≈2.65 times as many residents who were children or teenagers than were seniors.

The correct answer is 2.65.

2. If, at the time of the census, there were 540 more people aged 0–39 than people aged 40 or greater, then the population of Town Y at the time of the census was______________.

According to the graph, at the time of the census, 68% of residents were aged 0–39 and 32% were aged 40 or greater. If P represents the total population of Town Y, then \(540 = (0.68)P − (0.32)P.\) Therefore, 540 = 0.36P, so P\(=\frac{540}{0.36}=1,500.\)

The correct answer is 1,500.
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Since its mentioned as The census indicates that times as many residents were children "or" teenagers as were seniors.
Here I notice its mentioned as OR then why do we add both teeanger and child percentage
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UmerShariff

In this case, "or" means we definitely should add. After all, one person isn't both a child under 12 AND a teen. The idea is that the group of people who are EITHER children OR teens is 2.65 times the size of the senior group.
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I encountered a new question while doing practice problems today.

The question is: From the names in the census, one name is randomly chosen to receive prize A and one name (possibly the same) is randomly chosen to receive prize B. The probability that no child's name was chosen is (Select one).

The options are: 0.04, 0.16, 0.64, 0.84, 0.96.

I’m not sure how to approach this problem. Can someone help me? Thank you!"

Let me know if you'd like help with solving it!
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Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
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hattie
I encountered a new question while doing practice problems today.

The question is: From the names in the census, one name is randomly chosen to receive prize A and one name (possibly the same) is randomly chosen to receive prize B. The probability that no child's name was chosen is (Select one).

The options are: 0.04, 0.16, 0.64, 0.84, 0.96.

I’m not sure how to approach this problem. Can someone help me? Thank you!"

Let me know if you'd like help with solving it!

Could you please provide a screenshot of the question? Thank you!
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Hello, this is from a mock exam software. I have attached a screenshot in the attachment.
Bunuel
hattie
I encountered a new question while doing practice problems today.

The question is: From the names in the census, one name is randomly chosen to receive prize A and one name (possibly the same) is randomly chosen to receive prize B. The probability that no child's name was chosen is (Select one).

The options are: 0.04, 0.16, 0.64, 0.84, 0.96.

I’m not sure how to approach this problem. Can someone help me? Thank you!"

Let me know if you'd like help with solving it!

Could you please provide a screenshot of the question? Thank you!

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There is an interesting GMAT770 watermark in the image 👀
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for the second question, no child's name be selected with the prob of 0.8 which is 1-0.2. thus we just get 0.64 from 0.8*0.8=0.64
hattie
Hello, this is from a mock exam software. I have attached a screenshot in the attachment.
Bunuel
hattie
I encountered a new question while doing practice problems today.

The question is: From the names in the census, one name is randomly chosen to receive prize A and one name (possibly the same) is randomly chosen to receive prize B. The probability that no child's name was chosen is (Select one).

The options are: 0.04, 0.16, 0.64, 0.84, 0.96.

I’m not sure how to approach this problem. Can someone help me? Thank you!"

Let me know if you'd like help with solving it!

Could you please provide a screenshot of the question? Thank you!
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