A rectangle is inscribed in a hexagon that has all sides of equal leng

One shaded triangle = an equilateral triangle with side x

I.e. two shaded triangles = 2 equilateral triangles

Hexagon = 6 equilateral triangles

Shaded = hexagon/3 = x/3

Answer Option C

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let side of hexagon = 4
so total area of hexagon ; 6*4*4*√3/4 = 41.56( x)
and shaded part is nothing but area of two equilateral ∆ ; 2*16*√3/4 ; 13.8

put value of x in each option in C ; we get 41.56/3 ; 13.8
OPTION C

Two doubts:
1. The question does not state is a regular hexagon, why do you assume 6 equilateral triangles
2. 6 Equilateral Triangles are formed when a point from the center joins the 6 vertices. Here triangles are different

Only a regular polygon have equal sides and equal angles so it can be determined from the question statement.

Got it, Thanks

Bunuel How are we supposed to solve this under 2 mins.

I didn't understand your solution. Could you please explain how an hexagon contains 6 equilateral triangles ? Shouldn't it be 4 ? 2 at the top and bottom and 2 after dividing the rectangle into 2

tejasvkalra

Please check the video (from our Video course on geometry) attached here which explains how a hexagon is equivalent to 6 equilateral triangles

Very well explained +1 GMATinsight

Got it. Thanks

Rule: You can Divide a Regular Hexagon by using 3 Vertex to Opposite Vertex Diagonals into 6 Equilateral Triangles all with the Same Side as the Regular Hexagon.

If you FIRST Split the Regular Hexagon up into these 6 Equilateral Triangles and THEN add in the 2 Lines forming the Shaded Regions, you will see that the 2 Diagonals that form the Shaded Rectangles are Each (2) * (Height) of any 1 of the Equilateral Triangles.

Examining the picture, you see that the Top Shaded Portion is 1 of the Equilateral Triangles. Also, the Bottom Shaded Portion is 1 of the Equilateral Triangles.

Therefore, the Shaded Portion is Exactly 2 out of the 6 Equilateral Triangles that make up the Area of the Regular Hexagon.

If the Area of the Entire Regular Hexagon = X

Area of the 2 Shaded Regions = (2/6) * X = X/3

Answer C

BrentGMATPrepNow can you please explain this question. I am having trouble in visualizing the figure.

Thank you!

Hi Gmat Insight ,

I understand that Regular Hexagon is made up of 6 equilateral triangles. But how we know the shaded portion is 3 parts of it ??

We can divide the hexagon into 6 equilateral triangles, with each shaded triangle representing 1 equilateral triangle.

Each equilateral represents \(\frac{1}{6}x\)

Therefore 2 equilateral triangles represent \(\frac{x}{3}\).

Properties of a Regular Hexagon:
- It has six sides and six angles.
- Lengths of all the sides and the measurement of all the angles are equal.
- The total number of diagonals in a regular hexagon is 9.
- The sum of all interior angles is equal to 720 degrees, where each interior angle measures 120 degrees.

Answer is C.

BrentGMATPrepNow can you pls provide your solution

KarishmaB
how about an alternative solution where you subtract an area of rectangle from an area of hexagon

i did this but smth went wrong \(\frac{3*x^2 \sqrt{3} }{2 }- 2x^2\sqrt{3}\)


area of rectangle i got this way: each shaded region represents isosceles triangle, so if i draw perpendicular line i get 30:60:90 trangle


hence length of rectangle is \(2x\sqrt{3}\) and width x

I would much rather use the symmetry of a regular hexagon and the triangles I can carve out of it as done above.
But if you wanted to use geometry as suggested by you, note that x is the area of the hexagon, not a side.

Since a hexagon is made up of 6 equilateral triangles, its area will be \(6 * \frac{\sqrt{3} * a^2}{4} = x\) ... (I)

If side of the hexagon is a, in the 30-60-90 shaded triangle (half of each shaded triangle), the side opposite to 60 is \(\frac{\sqrt{3}a}{2}\) which means the width of the rectangle is \(\sqrt{3}a\).

Area of rectangle is \(a*\sqrt{3}a = \sqrt{3}a^2 = \frac{2x}{3}\) (from (I) above)

Shaded area\( = x - \frac{2x}{3} = \frac{x}{3}\)