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# A right circular cylinder with a radius of 2 feet and a length of 6 fe

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Math Expert
Joined: 02 Sep 2009
Posts: 58381
A right circular cylinder with a radius of 2 feet and a length of 6 fe  [#permalink]

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30 Oct 2018, 03:19
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Difficulty:

5% (low)

Question Stats:

91% (00:42) correct 9% (01:05) wrong based on 35 sessions

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A right circular cylinder with a radius of 2 feet and a length of 6 feet is cut into three equal pieces. What is the volume, in cubic feet, of each of the three pieces?

A. 2π
B. 3π
C. 8π
D. 12π
E. 24π

Attachment:

fig01.png [ 4.85 KiB | Viewed 582 times ]

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Re: A right circular cylinder with a radius of 2 feet and a length of 6 fe  [#permalink]

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30 Oct 2018, 03:22
Image
A right circular cylinder with a radius of 2 feet and a length of 6 feet is cut into three equal pieces. What is the volume, in cubic feet, of each of the three pieces?

A. 2π
B. 3π
C. 8π
D. 12π
E. 24π

=> each piece volume shall be
=>(π*r^2*h/3)
=> (π*2*2*6/3)
=> π8
option C
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Re: A right circular cylinder with a radius of 2 feet and a length of 6 fe  [#permalink]

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14 Mar 2019, 07:14
Bunuel wrote:

A right circular cylinder with a radius of 2 feet and a length of 6 feet is cut into three equal pieces. What is the volume, in cubic feet, of each of the three pieces?

A. 2π
B. 3π
C. 8π
D. 12π
E. 24π

Attachment:
fig01.png

The formula for the volume of a right circular cylinder is V = π x r^2 x h; thus, the volume of the entire cylinder is:

π x 2^2 x 6 = 24π ft^3

So when it’s cut into 3 equal pieces, the volume of each piece is 24π/3 = 8π ft^3.

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Re: A right circular cylinder with a radius of 2 feet and a length of 6 fe  [#permalink]

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14 Mar 2019, 17:58
$$V = π*R²*h = π*2²*2 = 8*π ft³$$

Ans C
Re: A right circular cylinder with a radius of 2 feet and a length of 6 fe   [#permalink] 14 Mar 2019, 17:58
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