Tking1167 wrote:

A salesperson travels weekly to a client's office and returns by the same route. If the salesperson travels to the client's office and then completes 25% of the return trip, what percent of the round-trip has been completed?

A 12.5%

B 25%

C 62.5%

D 75%

E 81%

Let the distance of one way trip to client's office be \(= 100\)

kmTherefore total distance of round trip \(= 100 + 100 = 200\)

kmSalesperson completes the one way trip, ie; \(= 100\)

kmThen Salesperson completes \(25\)

% of return trip, ie; \(= 25\)% of \(100 = \frac{25}{100} * 100 = 25\)

kmRequired percentage \(=\) ( Total distance completed \(/\) Total distance )\(* 100\)

Required percentage \(= \frac{100 + 25}{200} * 100 = \frac{125}{200} * 100 = 62.5\)

%Answer (C)..._________________

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