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A store sells chairs and tables. If the price of 3 chairs and 1 table is 60% of the price of 1 chair and 3 tables, and the price of 1 table and 1 chair is $60, what is the price, in dollars, of 1 table? (Assume that every chair has the same price and every table has the same price.)

Re: A store sells chairs and tables. If the price of 3 chairs and 1 table [#permalink]

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23 Jun 2015, 06:40

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C = price of a chair, T = price of a table, T = ? 3C + T = 0.6 (C + 3T) and T + C = 60 => 60 - T = C

3C + T = .6C + 1.8T => 3C - .6C = 1.8T - T 2.4C = .8T to make the math easier multiply by 10 and factor out 8..24C=8T => 3C = T 3 (60 - T) = T => 180 - 3T = T = > 180 = 4T T = 45

Re: A store sells chairs and tables. If the price of 3 chairs and 1 table [#permalink]

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23 Jun 2015, 07:05

Option D. 3x+y= (x+3y) * 0.6

12x=4y

Given x+y= 60.

Y=45(Table); X=15 (Chair)

Bunuel wrote:

A store sells chairs and tables. If the price of 3 chairs and 1 table is 60% of the price of 1 chair and 3 tables, and the price of 1 table and 1 chair is $60, what is the price, in dollars, of 1 table? (Assume that every chair has the same price and every table has the same price.)

A store sells chairs and tables. If the price of 3 chairs and 1 table is 60% of the price of 1 chair and 3 tables, and the price of 1 table and 1 chair is $60, what is the price, in dollars, of 1 table? (Assume that every chair has the same price and every table has the same price.)

(A) 15 (B) 20 (C) 30 (D) 40 (E) 45

Kudos for a correct solution.

Let, COst of Chair = C, Cost of Table = T

i.e. 3C+T = (60/100)*(C+3T) i.e. 3C+T = (3/5)*(C+3T) i.e. 15C + 5T = 3C + 9T i.e. 12C = 4T i.e. T = 3C

and T+C = 60 i.e. 3C + C = 60 i.e. C = $15 i.e. T = $45

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Re: A store sells chairs and tables. If the price of 3 chairs and 1 table [#permalink]

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23 Jun 2015, 11:23

Bunuel wrote:

A store sells chairs and tables. If the price of 3 chairs and 1 table is 60% of the price of 1 chair and 3 tables, and the price of 1 table and 1 chair is $60, what is the price, in dollars, of 1 table? (Assume that every chair has the same price and every table has the same price.)

(A) 15 (B) 20 (C) 30 (D) 40 (E) 45

Kudos for a correct solution.

From the text we know; 3C + 1T = 0.6(1C +3T) and: 1T + 1C = 60 >>> T = 60 - C

Plug in T in the formula above: 3C + 60 - C = 0.6C + 1.8(60-C) 2C + 60 = 108 - 1.2C 3.2C = 48 C = 15 T = 45

Answer E
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While this question can certainly be solved algebraically, it can also be solved rather easily by TESTing THE ANSWERS and doing a little arithmetic...

We're given a few facts to work with: 1) 3 chairs + 1 table = 60% of the price of (1 chair + 3 tables) 2) 1 chair + 1 table = $60 3) Each chair has the same price and each table has the same price

We're asked for the price of 1 table.

Since 3 chairs and 1 table cost LESS than 1 chair and 3 tables, a chair MUST cost LESS than a table. Since 1 chair + 1 table = $60, that means that 1 chair costs LESS than $30 and 1 table costs MORE than $30. There are only two answers that fit THIS pattern....

Let's TEST Answer D: $40

IF....1 table = $40.... 1 chair = $20 3 chairs + 1 table = $100 1 chair + 3 tables = $140 60% of $140 = $84 (not $100....so this CANNOT be the answer).

IF....1 table = $45.... 1 chair = $15 3 chairs + 1 table = $90 1 chair + 3 tables = $150 60% of $150 = $90 (this is a MATCH, so this MUST be the answer).

Re: A store sells chairs and tables. If the price of 3 chairs and 1 table [#permalink]

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26 Jun 2015, 07:51

Bunuel wrote:

A store sells chairs and tables. If the price of 3 chairs and 1 table is 60% of the price of 1 chair and 3 tables, and the price of 1 table and 1 chair is $60, what is the price, in dollars, of 1 table? (Assume that every chair has the same price and every table has the same price.)

(A) 15 (B) 20 (C) 30 (D) 40 (E) 45

Kudos for a correct solution.

Let T be the price of one table C be the price of one chair

T + C = 60 --- Equation 1 (3C + T) = (60/100) ( 3T + C) on solving we get T - 3C = 0 ---- Equation 2

Solving Equation 1 and 2 simultaneously we get T = 45.

A store sells chairs and tables. If the price of 3 chairs and 1 table [#permalink]

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28 Jun 2015, 13:31

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Ans is E Given, 3C + 1T =60/100(1C+3T) by solving we get, 3C=T Also given, C+T=60 substituting value for T , C= 15 T=6-15=45, hence Ans is E
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Re: A store sells chairs and tables. If the price of 3 chairs and 1 table [#permalink]

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25 Dec 2017, 22:46

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