Hi All,

While this question can certainly be solved algebraically, it can also be solved rather easily by TESTing THE ANSWERS and doing a little arithmetic...

We're given a few facts to work with:

1) 3 chairs + 1 table = 60% of the price of (1 chair + 3 tables)

2) 1 chair + 1 table = $60

3) Each chair has the same price and each table has the same price

We're asked for the price of 1 table.

Since 3 chairs and 1 table cost LESS than 1 chair and 3 tables, a chair MUST cost LESS than a table. Since 1 chair + 1 table = $60, that means that 1 chair costs LESS than $30 and 1 table costs MORE than $30. There are only two answers that fit THIS pattern....

Let's TEST Answer D: $40

IF....1 table = $40....

1 chair = $20

3 chairs + 1 table = $100

1 chair + 3 tables = $140

60% of $140 = $84 (not $100....so this CANNOT be the answer).

There's only one answer remaining....

Final Answer:

Here's the proof though....

IF....1 table = $45....

1 chair = $15

3 chairs + 1 table = $90

1 chair + 3 tables = $150

60% of $150 = $90 (this is a MATCH, so this MUST be the answer).

GMAT assassins aren't born, they're made,

Rich

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