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23 Jun 2015, 02:35
Kudos
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
83% (02:16) correct
17%
(02:37)
wrong
based on 309
sessions
History
Date
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Not Attempted Yet
A store sells chairs and tables. If the price of 3 chairs and 1 table is 60% of the price of 1 chair and 3 tables, and the price of 1 table and 1 chair is $60, what is the price, in dollars, of 1 table? (Assume that every chair has the same price and every table has the same price.)
(A) 15
(B) 20
(C) 30
(D) 40
(E) 45
Kudos for a correct solution.
(A) 15
(B) 20
(C) 30
(D) 40
(E) 45
Kudos for a correct solution.
23 Jun 2015, 07:40
Kudos
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C = price of a chair, T = price of a table, T = ?
3C + T = 0.6 (C + 3T) and T + C = 60 => 60 - T = C
3C + T = .6C + 1.8T => 3C - .6C = 1.8T - T
2.4C = .8T to make the math easier multiply by 10 and factor out 8..24C=8T => 3C = T
3 (60 - T) = T => 180 - 3T = T = > 180 = 4T
T = 45
3C + T = 0.6 (C + 3T) and T + C = 60 => 60 - T = C
3C + T = .6C + 1.8T => 3C - .6C = 1.8T - T
2.4C = .8T to make the math easier multiply by 10 and factor out 8..24C=8T => 3C = T
3 (60 - T) = T => 180 - 3T = T = > 180 = 4T
T = 45
23 Jun 2015, 08:05
Kudos
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Option D.
3x+y= (x+3y) * 0.6
12x=4y
Given x+y= 60.
Y=45(Table); X=15 (Chair)
3x+y= (x+3y) * 0.6
12x=4y
Given x+y= 60.
Y=45(Table); X=15 (Chair)
Bunuel
