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A total of s oranges are to be packaged in boxes that will hold r oran

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A total of s oranges are to be packaged in boxes that will hold r oran [#permalink]

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A total of s oranges are to be packaged in boxes that will hold r oranges each, with no oranges left over. When n of these boxes have been completely filled, what is the number of boxes that remain to be filled?

A) s-nr

B) s–(\(\frac{n}{r}\))

C) rs–n

D) (\(\frac{s}{n}\))–r

E) (\(\frac{s}{r}\))–n

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[Reveal] Spoiler: OA

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A total of s oranges are to be packaged in boxes that will hold r oran [#permalink]

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AbdurRakib wrote:
A total of s oranges are to be packaged in boxes that will hold r oranges each, with no oranges left over. When n of these boxes have been completely filled, what is the number of boxes that remain to be filled?

A) s-nr

B) s–(\(\frac{n}{r}\))

C) rs–n

D) (\(\frac{s}{n}\))–r

E) (\(\frac{s}{r}\))–n

OG 2017 New Question


One approach is to use the INPUT-OUTPUT approach.
Choose some INPUT values of s, r and n and see what the answer is OUTPUT is. Then check the answer choices to see which one yields the matching OUTPUT.

So, let's say there are 12 oranges (s = 12) and each box holds 3 oranges (r = 3).
Let's also say that we pack 2 of the boxes (n = 2)

Question: What is the number of boxes that remain to be filled?
If each box holds 3 oranges, then we'll need a total of 4 boxes to hold all 12 oranges.
So, if we pack 2 boxes, there will be 2 boxes remaining to be filled.

So, when we INPUT s = 12, r = 3 and n = 2 into the answer choices, the correct answer choice will be the one that yields an OUTPUT of 2

Now test the answer choices:
A) 12 - (2)(3) = 6 We want 2. ELIMINATE

B) 122/3 = 11 1/3 We want 2. ELIMINATE

C) (3)(12) – 2 = 34 We want 2. ELIMINATE

D) 12/2 - 3 = 3 We want 2. ELIMINATE

E) 12/32 = 2 BINGO!

Answer:
[Reveal] Spoiler:
E


Here's a video on this question type (Variables in the answer choices):


Here's a video with some tips to consifer when using the INPUT-OUTPUT approach:


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Last edited by GMATPrepNow on 01 May 2017, 06:00, edited 1 time in total.
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Re: A total of s oranges are to be packaged in boxes that will hold r oran [#permalink]

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New post 19 Nov 2016, 03:52
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Total = ‘s’ oranges.
Number of oranges in one box = ‘r’
Number of boxes = s/r
Number of boxes filled = n
Number of boxes that are yet to be filled = (s/r) – n

Answer: E
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Re: A total of s oranges are to be packaged in boxes that will hold r oran [#permalink]

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New post 19 Nov 2016, 05:02
if we take s=10, r=2 then 5 boxes will be filled. and if n=10 then 5 boxes will remain unfilled. so according to that (s-n/r) should be correct. so please correct if i am wrong.
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Re: A total of s oranges are to be packaged in boxes that will hold r oran [#permalink]

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AbdurRakib wrote:
A total of s oranges are to be packaged in boxes that will hold r oranges each, with no oranges left over. When n of these boxes have been completely filled, what is the number of boxes that remain to be filled?

A) s-nr

B) s–(\(\frac{n}{r}\))

C) rs–n

D) (\(\frac{s}{n}\))–r

E) (\(\frac{s}{r}\))–n

OG 2017 New Question


No of boxes required = \(\frac{s}{r}\)

n boxes have been filled , so no of boxes left is -

(\(\frac{s}{r}\))–n

Thus answer will be (E)

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Re: A total of s oranges are to be packaged in boxes that will hold r oran [#permalink]

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New post 20 Nov 2016, 01:02
AbdurRakib wrote:
A total of s oranges are to be packaged in boxes that will hold r oranges each, with no oranges left over. When n of these boxes have been completely filled, what is the number of boxes that remain to be filled?

A) s-nr

B) s–(\(\frac{n}{r}\))

C) rs–n

D) (\(\frac{s}{n}\))–r

E) (\(\frac{s}{r}\))–n

OG 2017 New Question


well this can be solved by plugging in numbers.
Let the total number of oranges= s= 100
Let the number of oranges per box= r= 10
let the number of boxes already filled= n=8
Now substitute these values and find out which of the options give you the answer 2.
(s/r)-n = (100/10)-8= 2
E
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Re: A total of s oranges are to be packaged in boxes that will hold r oran [#permalink]

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AbdurRakib wrote:
A total of s oranges are to be packaged in boxes that will hold r oranges each, with no oranges left over. When n of these boxes have been completely filled, what is the number of boxes that remain to be filled?

A) s-nr

B) s–(\(\frac{n}{r}\))

C) rs–n

D) (\(\frac{s}{n}\))–r

E) (\(\frac{s}{r}\))–n


Since s oranges are to be packaged in boxes that will hold r oranges each, the total number of boxes to be packed is s/r. Thus, after n boxes have been filled, the number of boxes left to be filled is (s/r) - n.

Answer: E
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Re: A total of s oranges are to be packaged in boxes that will hold r oran [#permalink]

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S/R=N
S/R-N=0, thus zero number of boxes is left to be packed. Answer E.
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Re: A total of s oranges are to be packaged in boxes that will hold r oran [#permalink]

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New post 01 May 2017, 05:56
Let there be ‘s’ oranges and ‘r’ oranges per box.
Total no. of boxes required will be (s/r) and “n” of them are currently filled
So, no. of boxes yet to be filled will be (s/r)-n.
OA: Option (E)
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Re: A total of s oranges are to be packaged in boxes that will hold r oran [#permalink]

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New post 17 Jan 2018, 12:40
Hi All,

This question can be solved by TESTing VALUES.

IF....
S = 6
R = 2

Then we're packing 6 oranges into boxes that will hold 2 oranges each... which means that there will be 3 boxes.

N = 1

So after 1 (of the 3) boxes is filled, there will be 2 boxes left. Thus, we're looking for an answer that equals 2 when we test the above three values.

Answer A: 6 - 2 = 4 NOT a match
Answer B: 6 - 1/2 = 5.5 NOT a match
Answer C: 12 - 1 = 11 NOT a match
Answer D: 6 - 2 = 4 NOT a match
Answer E: 3 - 1 = 2 This IS a match

Final Answer:
[Reveal] Spoiler:
E


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Re: A total of s oranges are to be packaged in boxes that will hold r oran   [#permalink] 17 Jan 2018, 12:40
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