Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

A train met with an accident 60km away from station A. It co [#permalink]

Show Tags

18 Oct 2011, 07:37

7

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

55% (hard)

Question Stats:

72% (03:20) correct 28% (05:37) wrong based on 187 sessions

HideShow timer Statistics

A train met with an accident 60km away from station A. It completed the remaining journey at 5/6th of the original speed and reached station B 1hr 12mins late. Had the accident taken place 60km further, it would have been only 1hr late. what was the original speed of the train?

A. 60 km/hr B. 55 km/hr C. 65 km/hr D. 70 km/hr E. 48 km/hr

A train met with an accident 60km away from station A. It completed the remaining journey at 5/6th of the original speed and reached station B 1hr 12mins late. Had the accident taken place 60km further, it would have been only 1hr late. what was the original speed of the train?

a. 60 km/hr b. 55 km/hr c. 65 km/hr d. 70 km/hr e. 48 km/hr

let the original speed be 6x. A/q, traveling 60 km at 5/6th of original speed costs him 12 minutes etc

My solution: s=original spped, t=time taken in minutes to cover journey usually (t+72-60/s)(5/6s)+60=(t+60-120/s)(5/6s)+120...........as total distance covered is same in both cases solving, s=1 km/min=60km/hr hence ans A I know its too long.....but taking shortcuts was messing me up....

A train met with an accident 60km away from station A. It completed the remaining journey at 5/6th of the original speed and reached station B 1hr 12mins late. Had the accident taken place 60km further, it would have been only 1hr late. what was the original speed of the train?

a. 60 km/hr b. 55 km/hr c. 65 km/hr d. 70 km/hr e. 48 km/hr

The logical approach here is this:

The accident took place 60 km from A. The train was delayed by 1hr 12 min. If it had instead taken place 120 km from A, it would have been only 1 hr late. What does this 12 min gap in time signify? It is the delay caused by reducing the speed by (1/6)th over a distance of 60 km. The ratio of the speed over this 60 km stretch is 5:6 (speed reduced by a sixth : original speed) Time taken 6:5 (Time taken with reduced speed : original time taken) We know this difference of 1 in time taken is given by 12 min. So original time taken is 12*5 = 60 min = 1 hr Time taken is 1 hr to cover a distance of 60 km so speed = 60 km/hr
_________________

In case 2, the 60 kms further which the train traveled was with speed v. In case 1, these 60 kms (which in case 2 the train traveled further where accident happened) was traveled at a speed of (5v)/6. And this caused the extra 12 mins delay in case 1.

Re: A train met with an accident 60km away from station A. It co [#permalink]

Show Tags

14 Feb 2014, 02:36

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

Can someone please help me think through this problem?

Given: It arrives 1 hr 12 min late if the accident took 60 km further from A It arrives 1 hr late if the accident took 120 km further from A

It implies: the two "accident spots" are separated by 12 min and 60 km

Hence: R = (60)*(60/12) = 300 kmph

You are assuming that the train covered 60 km in 12 mins. That gives you the speed as 300 kmph. But is that really the case? 12 mins is the difference in the time taken to cover 60 kms at two different speeds. It is the delay caused by reducing the speed by (1/6)th over a distance of 60 km. The ratio of the speed over this 60 km stretch is 5:6 (speed reduced by a sixth : original speed)

Time taken 6:5 (Time taken with reduced speed : original time taken)

We know this difference of 1 in time taken is given by 12 min. So original time taken is 12*5 = 60 min = 1 hr

Time taken is 1 hr to cover a distance of 60 km so speed = 60 km/hr
_________________

Re: A train met with an accident 60km away from station A. It co [#permalink]

Show Tags

24 Apr 2017, 12:28

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

Re: A train met with an accident 60km away from station A. It co [#permalink]

Show Tags

01 May 2017, 00:18

A bit short method Assume that 1 hr late is the correct time, means that 120 km is the total distance (when accident took 60 km further after the first accident place) Therefore, 60/x + 60/(5x/6) = t + .2(delay) t = 120/x solve for x x= 60

A train met with an accident 60km away from station A. It completed the remaining journey at 5/6th of the original speed and reached station B 1hr 12mins late. Had the accident taken place 60km further, it would have been only 1hr late. what was the original speed of the train?

A. 60 km/hr B. 55 km/hr C. 65 km/hr D. 70 km/hr E. 48 km/hr

Speed (S) = Distance (D) / Time (T) D = S * T

i.e. Delay in travelling 60 Km at slower speed (5/6 speed) due to accident is 12 mins (1/5T)

i.e. 1/5 T = 12 T = 60 Mins to travel 60 km

Speed = 60/(60/60) = 60 Km/Hr
_________________

Prosper!!! GMATinsight Bhoopendra Singh and Dr.Sushma Jha e-mail: info@GMATinsight.com I Call us : +91-9999687183 / 9891333772 Online One-on-One Skype based classes and Classroom Coaching in South and West Delhi http://www.GMATinsight.com/testimonials.html